Answer
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Hint: In order to solve the Trigonometric Numerical , we need to know all the Identities by heart in order to solve the numerical . First step is to identify the type of identity to be used based on the trigonometric function given in the question. Since there are several identities for a single function, the next step is to decide which particular identity would suffice in order to solve the problem. It is also Advisable to Know the Maximum value , Minimum value and value for $ \dfrac{\pi }{6}\& {60^ \circ } $ for all trigonometric functions
Complete step-by-step answer:
From the above question we can figure it out that we have to make use of the Trigonometry identities in order to find the correct answer. Since the problem involves $ \sin x $ & $ \cos x $ we will have to make use of identity
$ {\sin ^2}\theta + {\cos ^2}\theta = 1..........(1) $
Given : $ 4{\sin ^2}x + 3{\cos ^2}x $
Restructuring $ Equation1 $ :
$ {\cos ^2}\theta = 1 - {\sin ^2}\theta ..........(2) $
Substituting value of \[{\cos ^2}\theta \]from $ Equation2 $ into the given problem
We are replacing $ \theta $ with $ x $ , since the question consists of $ x $ . There is no compulsion on using $ \theta $ with Trigonometric functions.
\[ \Rightarrow 4{\sin ^2}x + 3 \times (1 - {\sin ^2}x)\]
On simplifying the above equation and on opening the brackets we will get the following equation
$ \Rightarrow 4{\sin ^2}x + 3 - 3{\sin ^2}x........(3) $
Further Simplifying the $ Equation3 $ in order to bring it to non-reducible form
$ \Rightarrow {\sin ^2}x + 3.......(4) $
Now remembering the properties of $ \sin x $ we can say that the value of $ \sin x $ ranges from $ - 1 $ to $ 1 $ .
Thus the maximum value of $ \sin x $ will always be $ 1 $ . Thus the maximum value of \[{\sin ^2}x\] will be $ 1 $ .
$ \therefore $ Substituting Maximum Value of $ {\sin ^2}x $ $ Equation4 $
Final answer on substituting would be $ 4 $ .
Thus the maximum value of $ 4{\sin ^2}x + 3{\cos ^2}x $ is $ 4 $ .
From the given options, the correct option is $ OptionB $ which has a value of $ 4 $ .
So, the correct answer is “Option B”.
Note: It is also Advisable to Know the Maximum value , Minimum value and value $ \dfrac{\pi }{6}\& {60^ \circ } $ for all trigonometric functions. This is because in almost all the sums these are the standard angles based on which the questions are asked. Apart from these , memorizing the formulas and the relationship between various trigonometric functions is extremely vital.
Complete step-by-step answer:
From the above question we can figure it out that we have to make use of the Trigonometry identities in order to find the correct answer. Since the problem involves $ \sin x $ & $ \cos x $ we will have to make use of identity
$ {\sin ^2}\theta + {\cos ^2}\theta = 1..........(1) $
Given : $ 4{\sin ^2}x + 3{\cos ^2}x $
Restructuring $ Equation1 $ :
$ {\cos ^2}\theta = 1 - {\sin ^2}\theta ..........(2) $
Substituting value of \[{\cos ^2}\theta \]from $ Equation2 $ into the given problem
We are replacing $ \theta $ with $ x $ , since the question consists of $ x $ . There is no compulsion on using $ \theta $ with Trigonometric functions.
\[ \Rightarrow 4{\sin ^2}x + 3 \times (1 - {\sin ^2}x)\]
On simplifying the above equation and on opening the brackets we will get the following equation
$ \Rightarrow 4{\sin ^2}x + 3 - 3{\sin ^2}x........(3) $
Further Simplifying the $ Equation3 $ in order to bring it to non-reducible form
$ \Rightarrow {\sin ^2}x + 3.......(4) $
Now remembering the properties of $ \sin x $ we can say that the value of $ \sin x $ ranges from $ - 1 $ to $ 1 $ .
Thus the maximum value of $ \sin x $ will always be $ 1 $ . Thus the maximum value of \[{\sin ^2}x\] will be $ 1 $ .
$ \therefore $ Substituting Maximum Value of $ {\sin ^2}x $ $ Equation4 $
Final answer on substituting would be $ 4 $ .
Thus the maximum value of $ 4{\sin ^2}x + 3{\cos ^2}x $ is $ 4 $ .
From the given options, the correct option is $ OptionB $ which has a value of $ 4 $ .
So, the correct answer is “Option B”.
Note: It is also Advisable to Know the Maximum value , Minimum value and value $ \dfrac{\pi }{6}\& {60^ \circ } $ for all trigonometric functions. This is because in almost all the sums these are the standard angles based on which the questions are asked. Apart from these , memorizing the formulas and the relationship between various trigonometric functions is extremely vital.
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