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The major product formed is:${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - CH = C}}{{\text{H}}_{\text{2}}}{\text{ + HBr}} \to {\text{?}}$ A.${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - C}}{{\text{H}}_{\text{2}}}{\text{ - Br}}$B.${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - CH}}\left( {{\text{Br}}} \right){\text{ - C}}{{\text{H}}_{\text{3}}}$C.${\text{C}}{{\text{H}}_{\text{2}}}{\text{Br - CH = C}}{{\text{H}}_{\text{2}}}$D.${\text{C}}{{\text{H}}_{\text{2}}}{\text{ = C = C}}{{\text{H}}_{\text{2}}}$

Last updated date: 18th Mar 2023
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Hint: We also remember that in organic chemistry, hydrocarbons are an important topic. The hydrocarbons are majorly classified as three groups. There are alkane, alkene and alkyne. The alkane means carbon-carbon single bond. The alkene has a carbon-carbon double bond. The alkyne means carbon-carbon having triple bonds in the molecule.

${\text{C}}{{\text{H}}_{\text{3}}}{\text{ - CH = C}}{{\text{H}}_{\text{2}}}{\text{ + HBr}} \to {\text{C}}{{\text{H}}_{\text{3}}}{\text{ - CH}}\left( {{\text{Br}}} \right){\text{ - C}}{{\text{H}}_{\text{3}}}$
We must know the conversion of one type of hydrocarbon to another hydrocarbon by oxidation and reduction. The oxidation of alkane to give alkene. The oxidation of alkene to give alkyne. The reduction of alkyne to give alkene. The reduction of alkene to give alkane. It has some general formulas. The general formula of alkane is ${{\text{C}}_{\text{n}}}{{\text{H}}_{{\text{2n + 2}}}}$. The general formula of alkene is ${{\text{C}}_{\text{n}}}{{\text{H}}_{{\text{2n}}}}$. The general formula of alkyne is ${{\text{C}}_{\text{n}}}{{\text{H}}_{{\text{2n - 2}}}}$.