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Hint: Length, breadth and height are in the ratio $5$:$4$:$2$. Length will be $5x$, breadth will $4x$ and height will be $2x$. Use the formula of total surface area of cuboid to find the value of $x$.

Let the $l, b$ and $h$ be the length, breadth and height of the cuboid respectively. Then according to question:

$ \Rightarrow $$l$:$b$:$h$$ = $ $5$:$4$:$2$.

Therefore let $l = 5x$, $b = 4x $and $h = 2x$.

Total surface area of the cuboid given in the question is $1216c{m^2}$. And we know that:

Total surface area of cuboid $ = 2\left( {lb + bh + lh} \right)$.

So, putting all values from above:

\[

\Rightarrow 2\left( {lb + bh + lh} \right) = 1216, \\

\Rightarrow (5x)(4x) + (4x)(2x) + (5x)(2x) = 608, \\

\Rightarrow 20{x^2} + 8{x^2} + 10{x^2} = 608, \\

\Rightarrow 38{x^2} = 608, \\

\Rightarrow {x^2} = 16, \\

\Rightarrow x = 4. \\

\]

Putting the value of $x$in $l,b$and$h$. We’ll get:

$

\Rightarrow l = 5x = 20cm, \\

\Rightarrow b = 4x = 16cm, \\

\Rightarrow h = 2x = 8cm \\

$

Therefore, the dimensions of cuboid are $\left( {20 \times 16 \times 8} \right)c{m^3}$. (B) is the correct option.

Note: A cuboid consists of $6$ rectangular faces. Two of them have dimensions $(l \times b)c{m^2}$, another two have dimensions $(b \times h)c{m^2}$ and the rest two have dimensions\[(l \times h)c{m^2}\]. Therefore, the total surface area of the cuboid becomes $(2lb + 2bh + 2lh) = 2(lb + bh + lh)$ which we have used earlier. If all the dimensions $l,b$and$h$ are the same then it becomes a cube and in that case the total surface area is $6{l^2}$.

Let the $l, b$ and $h$ be the length, breadth and height of the cuboid respectively. Then according to question:

$ \Rightarrow $$l$:$b$:$h$$ = $ $5$:$4$:$2$.

Therefore let $l = 5x$, $b = 4x $and $h = 2x$.

Total surface area of the cuboid given in the question is $1216c{m^2}$. And we know that:

Total surface area of cuboid $ = 2\left( {lb + bh + lh} \right)$.

So, putting all values from above:

\[

\Rightarrow 2\left( {lb + bh + lh} \right) = 1216, \\

\Rightarrow (5x)(4x) + (4x)(2x) + (5x)(2x) = 608, \\

\Rightarrow 20{x^2} + 8{x^2} + 10{x^2} = 608, \\

\Rightarrow 38{x^2} = 608, \\

\Rightarrow {x^2} = 16, \\

\Rightarrow x = 4. \\

\]

Putting the value of $x$in $l,b$and$h$. We’ll get:

$

\Rightarrow l = 5x = 20cm, \\

\Rightarrow b = 4x = 16cm, \\

\Rightarrow h = 2x = 8cm \\

$

Therefore, the dimensions of cuboid are $\left( {20 \times 16 \times 8} \right)c{m^3}$. (B) is the correct option.

Note: A cuboid consists of $6$ rectangular faces. Two of them have dimensions $(l \times b)c{m^2}$, another two have dimensions $(b \times h)c{m^2}$ and the rest two have dimensions\[(l \times h)c{m^2}\]. Therefore, the total surface area of the cuboid becomes $(2lb + 2bh + 2lh) = 2(lb + bh + lh)$ which we have used earlier. If all the dimensions $l,b$and$h$ are the same then it becomes a cube and in that case the total surface area is $6{l^2}$.

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