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The $\left( X \right)$ and $\left( Y \right)$ formed in the below two reactions are:
$B{e_2}C + 4{H_2}O \to 2X + C{H_4}$
$X + 2OH \to Y$
A.\[BeC{O_3}\] and ${\text{Be}}{\left( {OH} \right)_2}$ respectively
B.${\text{Be}}{\left( {OH} \right)_2}$ and ${\text{BeC}}{{\text{l}}_2}$ respectively
C.$Be{\left( {OH} \right)_2}$ and ${\left[ {Be{{\left( {OH} \right)}_4}} \right]^{2 - }}$ respectively
D.${\left[ {Be{{\left( {OH} \right)}_4}} \right]^{2 - }}$ and ${\text{BeC}}{{\text{l}}_2}$ respectively

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Last updated date: 22nd Feb 2024
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IVSAT 2024
Answer
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Hint: We have to know that the chemical responses are surrounding us, from the digestion of food in our body to how the light we get from the sun is the aftereffect of compound responses. Prior to starting with compound responses, it is imperative to think about physical and substance changes.

Complete answer:
We have to see, the consuming light is the best illustration of physical and compound change. Take a flame and light it. Over the long haul, we can see that the flame changes to wax. On the off chance that you cover the candle with a container, it will smother.
In the exhibition, the consuming of the flame is a compound change while transformation of the light to wax is an actual change. In an actual change, there is essentially a difference in condition of the substance however on account of a compound change for the most part another substance is shaped in which either energy is emitted or consumed. In this way, we can reason that substance changes are joined by certain actual changes.
Because of the huge measures of synthetic responses occurring around us, a classification was created to work on how we express a substance response as a compound condition. A substance condition is only a numerical proclamation which represents the item arrangement from reactants while expressing certain conditions for how the response has been directed.
Then, in the given question,
$B{e_2}C + 4{H_2}O \to 2Be{\left( {OH} \right)_2} + C{H_4}$
$Be{\left( {OH} \right)_2} + 2OH \to {\left[ {Be{{\left( {OH} \right)}_4}} \right]^{2 - }}$

Therefore, option (C) $Be{\left( {OH} \right)_2}$ and ${\left[ {Be{{\left( {OH} \right)}_4}} \right]^{2 - }}$ respectively is correct answer.

Note:
We have to know the general chemical reaction, $A + B \to C + D$ .
Where, A and B are the reactants, which respond to shape the items C and D. In a real compound condition, reactants are indicated by their synthetic equation. To guarantee the law of preservation of mass, a synthetic condition should be adjusted for example the quantity of atoms on the two sides should be equivalent. This is the adjusting of the condition.
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