The income of a person is Rs.300,000 in the first year and he receives an increase of Rs.10000 to his income per year for the next 19 years. Find the total amount he received in 20 years.
Answer
326.7k+ views
Hint: Take the income of the person in the first year as ‘a’ and the amount by which it increases every year as ‘d’. Now the salary of each year would form A.P. Find the total amount he received in 20 years by using the formula for the sum of n terms of A.P that is \[{{S}_{n}}=\dfrac{n}{2}\left[ 2a+\left( n-1 \right)d\right]\]
Complete step by step solution:
Here we are given that the income of a person is Rs.300,000 in the first year and it increases every year for the next 19 years by Rs.10000. We have to find the total amount he received in 20 years.
Let us consider the income of the person in the first year as
a = Rs.300,000
Also, let us consider the amount by which the income is getting increased every year as d = Rs.10000.
So, we get the income of a man in the first year = a.
Also, the income of a man in the second year = a + d.
Similarly, the income of a man in the third year = a + 2d.
This would continue for a total of 20 years.
So, we get the series of income of a man in each year as
a, a + d, a + 2d, a + 3d………
Here, we can see the income of a man in each year in A.P with a = Rs.300,000 as first term and d = Rs.10000 as a common difference.
We know that sum of n terms of A.P \[=\dfrac{n}{2}\left[ 2a+\left( n-1 \right)d \right]....\left( i \right)\]
Now, we have to find the total amount he received in 20 years. So, we have to add his income from the first year to the 20 th year. As we know that his income is in A.P. So, we get
Total amount received by man in 20 years = Sum of 20 terms of A.P \[\left( {{S}_{20}} \right)....\left( ii \right)\]
By substituting the value of n = 20, a = 300,000 and d = 10000 in equation (i), we get,
Sum of 20 terms of A.P \[=\left( {{S}_{20}} \right)=\dfrac{20}{2}\left[ 2\times \left( 300000 \right)+\left(
20-1 \right)\left( 10000 \right) \right]\]
\[{{S}_{20}}=10\left( 600000+190000 \right)\]
\[=10\left( 790000 \right)\]
\[=79,00,000\]
By substituting the value of \[{{S}_{20}}\] in equation (ii), we get,
Total amount received by man in 20 years = Rs.7900000
So, we get the total amount received by man in 20 years as Rs 79 lakhs
Note: Here, some students try to manually find the total amount by adding the income of each year one by one. But this method is very lengthy and can even give wrong results if there would be even a slight mistake in calculation. So students must identify the series in these types of questions and accordingly use the formula of the sum of n terms.
Complete step by step solution:
Here we are given that the income of a person is Rs.300,000 in the first year and it increases every year for the next 19 years by Rs.10000. We have to find the total amount he received in 20 years.
Let us consider the income of the person in the first year as
a = Rs.300,000
Also, let us consider the amount by which the income is getting increased every year as d = Rs.10000.
So, we get the income of a man in the first year = a.
Also, the income of a man in the second year = a + d.
Similarly, the income of a man in the third year = a + 2d.
This would continue for a total of 20 years.
So, we get the series of income of a man in each year as
a, a + d, a + 2d, a + 3d………
Here, we can see the income of a man in each year in A.P with a = Rs.300,000 as first term and d = Rs.10000 as a common difference.
We know that sum of n terms of A.P \[=\dfrac{n}{2}\left[ 2a+\left( n-1 \right)d \right]....\left( i \right)\]
Now, we have to find the total amount he received in 20 years. So, we have to add his income from the first year to the 20 th year. As we know that his income is in A.P. So, we get
Total amount received by man in 20 years = Sum of 20 terms of A.P \[\left( {{S}_{20}} \right)....\left( ii \right)\]
By substituting the value of n = 20, a = 300,000 and d = 10000 in equation (i), we get,
Sum of 20 terms of A.P \[=\left( {{S}_{20}} \right)=\dfrac{20}{2}\left[ 2\times \left( 300000 \right)+\left(
20-1 \right)\left( 10000 \right) \right]\]
\[{{S}_{20}}=10\left( 600000+190000 \right)\]
\[=10\left( 790000 \right)\]
\[=79,00,000\]
By substituting the value of \[{{S}_{20}}\] in equation (ii), we get,
Total amount received by man in 20 years = Rs.7900000
So, we get the total amount received by man in 20 years as Rs 79 lakhs
Note: Here, some students try to manually find the total amount by adding the income of each year one by one. But this method is very lengthy and can even give wrong results if there would be even a slight mistake in calculation. So students must identify the series in these types of questions and accordingly use the formula of the sum of n terms.
Last updated date: 30th May 2023
•
Total views: 326.7k
•
Views today: 5.83k
Recently Updated Pages
Calculate the entropy change involved in the conversion class 11 chemistry JEE_Main

The law formulated by Dr Nernst is A First law of thermodynamics class 11 chemistry JEE_Main

For the reaction at rm0rm0rmC and normal pressure A class 11 chemistry JEE_Main

An engine operating between rm15rm0rm0rmCand rm2rm5rm0rmC class 11 chemistry JEE_Main

For the reaction rm2Clg to rmCrmlrm2rmg the signs of class 11 chemistry JEE_Main

The enthalpy change for the transition of liquid water class 11 chemistry JEE_Main

Trending doubts
Difference Between Plant Cell and Animal Cell

Write an application to the principal requesting five class 10 english CBSE

Ray optics is valid when characteristic dimensions class 12 physics CBSE

Give 10 examples for herbs , shrubs , climbers , creepers

Write the 6 fundamental rights of India and explain in detail

Write a letter to the principal requesting him to grant class 10 english CBSE

List out three methods of soil conservation

Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE

Write a letter to the Principal of your school to plead class 10 english CBSE
