Question

The given table shows the average temperature of some cities in India in a particular month.

City	Average maximum temperature	Average minimum temperature
New Delhi	\[{39^ \circ }C\]	\[{27^ \circ }C\]
Mumbai	\[{36^ \circ }C\]	\[{19^ \circ }C\]
Ahmadabad	\[{37^ \circ }C\]	\[{19^ \circ }C\]
Chennai	\[{42^ \circ }C\]	\[{26^ \circ }C\]
Kolkata	\[{38^ \circ }C\]	\[{24^ \circ }C\]

Which city has the highest difference, its average maximum temperature and average minimum temperature?
I.Kolkata
II.Mumbai
III.Chennai
IV.Ahmedabad

Answer 1

Hint: Subtract average minimum temperature from average maximum temperature.
The average is something that represents a middle point. The average is the quotient obtained by dividing the sum total of a set of figures by the number of figures.

Complete step-by-step answer:
A range is a difference between the largest and smallest numbers. The midrange is the average of largest and smallest numbers.
Average maximum is the average of all largest numbers obtained when an experiment or the observation is done for a particular period of time whereas the average minimum is the average of all smallest numbers obtained for that experiment or the observation.
Here, in this question we need to determine the highest difference in the average of the maximum and the minimum temperature.
In the question, average maximum temperature and average minimum temperature are given where the average maximum temperature is the average of all the maximum temperature observed on a day of a city for a particular month, and average minimum temperature is the minimum temperature observed in a particular month.
Highest difference= Average maximum temperature – Average minimum temperature
So the highest difference of temperature of each city:
New Delhi \[ = {39^ \circ }C - {27^ \circ }C = {12^ \circ }C\]
Mumbai\[ = {36^ \circ }C - {19^ \circ }C = {17^ \circ }C\]
Ahmadabad\[ = {37^ \circ }C - {19^ \circ }C = {18^ \circ }C\]
Chennai\[ = {42^ \circ }C - {26^ \circ }C = {16^ \circ }C\]
Kolkata\[ = {38^ \circ }C - {24^ \circ }C = {14^ \circ }C\]
Therefore the highest difference \[ = {18^ \circ }C\]
Hence the city with the highest difference in Ahmedabad
So, the correct answer is “Option D”.

Note: Average maximum temperature for a month is calculated by the ratio of the sum of all maximum temperature of each day divided by the total number of days.