Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# The given circuit is a part of a certain network. The potential difference

Last updated date: 18th Jun 2024
Total views: 374.4k
Views today: 10.74k
Verified
374.4k+ views
Hint: In this question we have been asked to calculate the potential difference between the two points of the given part of circuit. To solve this question, we shall calculate the current flowing through each arm and later using Ohm's law, we shall calculate the potential across the given points. While solving we must remember that the potential difference in the direction of current is taken as negative.

In the given diagram, the current in the arm PO is not given. Therefore, we shall calculate the current in the arm PO.
Now, in the given figure, we can see that the current in arm OM is 6 Amperes. This current is then split between arm PO and OQ. The current flowing in arm OQ is 3 Amperes. Therefore, the remaining current will flow in the arm OP. The magnitude of the current shall be 3 Amperes and the direction as shown in the figure below.

Now, using Kirchhoff’s rule
We can say that,
${{V}_{P}}-10V+3\times 1-3\times 1-3\times 3={{V}_{Q}}$
Therefore, on solving
We get,
${{V}_{P}}-{{V}_{Q}}=10+3-3+9$
Therefore,
${{V}_{P}}-{{V}_{Q}}=19V$
Therefore, the potential across points PQ is 19 Volts.

Note:
The Ohm’s Law states that the current in a circuit is directly proportional to the voltage applied and inversely proportional to the total resistance in the circuit. Potential difference or voltage can be defined as the amount of work needed per unit charge to move that charge between two given points. The unit of potential difference was named after Alessandro Volta.