Answer
Verified
441.3k+ views
Hint: Freezing point refers to the temperature at which a liquid becomes a solid, as with the melting point, increased pressure usually raises the freezing point. The freezing point is lower than the melting point in the case of mixtures and for certain organic compounds like fats.
Complete answer:
Colligative properties are properties that vary in terms of solvent concentration, but not in terms of the form of solution. For the example above, what this implies is that people in colder climates do not actually need salt to have the same impact on the roads-any solvent will work. The higher the solute concentration, however, the more these properties change.
Elevation of the boiling point is the increase of the boiling point of a solvent due to the addition of a solvent. Similarly, freezing point depression is a loss of the freezing point of a liquid due to the addition of a solution. Indeed, when a solvent's boiling point increases, its freezing point shrinks. An example of that would be to apply salt to an icy sidewalk. The solvent (salt) decreases the Ice freezing point, causing the ice to melt at a lower temperature.
Given:
\[\Delta {{H}_{fusion}}=10.042KJ/mol\]
\[{{T}_{f}}=278.4k\]
\[2C{{H}_{3}}COOH{{\left( C{{H}_{3}}COO \right)}_{2}}\]
\[C\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ O\]
\[C\left( 1-\alpha \right)\ \ \ \ \ \ \ \ C\dfrac{\alpha }{2}\]
\[{{k}_{c}}=\dfrac{C\dfrac{\alpha }{2}}{{{C}^{2}}{{\left( 1-\alpha \right)}^{2}}}=\dfrac{C\alpha }{2{{C}^{2}}{{\left( 1-\alpha \right)}^{2}}}\]
\[\]
\[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\]
So, Dimer is forming : \[\eta =2\]
\[\]
\[\alpha =\left( 1-i \right)\times 2\]
\[\]
Putting value in equation:
\[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\]
\[\Delta {{T}_{f}}=1-\dfrac{\alpha }{2}\times {{K}_{f}}\times m\]
\[\Delta {{T}_{f}}=1-\dfrac{\alpha }{2}\times 5\times m\]
\[\]
\[m=\dfrac{0.02\times 1000}{0.98\times 78}=0.262\,molal\]
So, \[C=0.262\,molal\]
\[\Delta {{T}_{f}}=5\times 0.262\times \left( 1-\dfrac{\alpha }{2} \right)\]
\[278.4-277.4=5\times 0.262\times \left( 1-\dfrac{\alpha }{2} \right)\]
\[\alpha =0.48\]
\[{{k}_{c}}=\dfrac{C\alpha }{2{{C}^{2}}{{\left( 1-\alpha \right)}^{2}}}\]
\[{{k}_{c}}=\dfrac{0.262\times 0.48}{2\times {{\left( 0.262 \right)}^{2}}{{\left( 1-0.48 \right)}^{2}}}\]
\[{{k}_{c}}=3.39\sim 3.2\]
Note:
-So, \[\Delta {{T}_{f}}=T_{f}^{0}-{{T}_{f}}\]
$\alpha $= Degree of dissociation
i= Van't Hoff factor
$\eta $= No. of ions obtained on association or dissociation
- Boiling point and freezing points are colligative properties of a solution.
-The factor of van' t Hoff I is a measure of the impact of a solution on colligative properties such as osmotic pressure, relative decrease in vapour pressure, of the elevation in boiling point and the depression in freezing point.
Complete answer:
Colligative properties are properties that vary in terms of solvent concentration, but not in terms of the form of solution. For the example above, what this implies is that people in colder climates do not actually need salt to have the same impact on the roads-any solvent will work. The higher the solute concentration, however, the more these properties change.
Elevation of the boiling point is the increase of the boiling point of a solvent due to the addition of a solvent. Similarly, freezing point depression is a loss of the freezing point of a liquid due to the addition of a solution. Indeed, when a solvent's boiling point increases, its freezing point shrinks. An example of that would be to apply salt to an icy sidewalk. The solvent (salt) decreases the Ice freezing point, causing the ice to melt at a lower temperature.
Given:
\[\Delta {{H}_{fusion}}=10.042KJ/mol\]
\[{{T}_{f}}=278.4k\]
\[2C{{H}_{3}}COOH{{\left( C{{H}_{3}}COO \right)}_{2}}\]
\[C\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ O\]
\[C\left( 1-\alpha \right)\ \ \ \ \ \ \ \ C\dfrac{\alpha }{2}\]
\[{{k}_{c}}=\dfrac{C\dfrac{\alpha }{2}}{{{C}^{2}}{{\left( 1-\alpha \right)}^{2}}}=\dfrac{C\alpha }{2{{C}^{2}}{{\left( 1-\alpha \right)}^{2}}}\]
\[\]
\[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\]
So, Dimer is forming : \[\eta =2\]
\[\]
\[\alpha =\left( 1-i \right)\times 2\]
\[\]
Putting value in equation:
\[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\]
\[\Delta {{T}_{f}}=1-\dfrac{\alpha }{2}\times {{K}_{f}}\times m\]
\[\Delta {{T}_{f}}=1-\dfrac{\alpha }{2}\times 5\times m\]
\[\]
\[m=\dfrac{0.02\times 1000}{0.98\times 78}=0.262\,molal\]
So, \[C=0.262\,molal\]
\[\Delta {{T}_{f}}=5\times 0.262\times \left( 1-\dfrac{\alpha }{2} \right)\]
\[278.4-277.4=5\times 0.262\times \left( 1-\dfrac{\alpha }{2} \right)\]
\[\alpha =0.48\]
\[{{k}_{c}}=\dfrac{C\alpha }{2{{C}^{2}}{{\left( 1-\alpha \right)}^{2}}}\]
\[{{k}_{c}}=\dfrac{0.262\times 0.48}{2\times {{\left( 0.262 \right)}^{2}}{{\left( 1-0.48 \right)}^{2}}}\]
\[{{k}_{c}}=3.39\sim 3.2\]
Note:
-So, \[\Delta {{T}_{f}}=T_{f}^{0}-{{T}_{f}}\]
$\alpha $= Degree of dissociation
i= Van't Hoff factor
$\eta $= No. of ions obtained on association or dissociation
- Boiling point and freezing points are colligative properties of a solution.
-The factor of van' t Hoff I is a measure of the impact of a solution on colligative properties such as osmotic pressure, relative decrease in vapour pressure, of the elevation in boiling point and the depression in freezing point.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
Give 10 examples for herbs , shrubs , climbers , creepers
10 examples of evaporation in daily life with explanations
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE