Answer
Verified
427.8k+ views
Hint: - Use the property, sum of infinite terms G.P as \[\dfrac{{{a_1}}}{{1 - r}}\]
It is given that the first term of an infinite G.P is 1.
\[ \Rightarrow {a_1} = 1\]
Now, we know the sum of infinite G.P \[\left( {{S_\infty }} \right) = \dfrac{{{a_1}}}{{1 - r}}\], (where r is the common ratio)
Let the infinite G.P series is
\[{a_1},{\text{ }}{a_1}r,{\text{ }}{a_1}{r^2}{\text{, }}{a_1}{r^3}{\text{, }}........................\infty \]
Therefore the sum of this series is
\[{S_\infty } = {a_1} + {a_1}r + {a_1}{r^2} + {a_1}{r^3} + ........................\infty = \dfrac{{{a_1}}}{{1 - r}}................\left( 1 \right)\]
Now according to question it is given that any term is equal to the sum of succeeding terms
\[ \Rightarrow {a_1} = {a_1}r + {a_1}{r^2} + {a_1}{r^3} + ........................\infty \]
Now add both sides by \[{a_1}\]
\[ \Rightarrow {a_1} + {a_1} = {a_1} + {a_1}r + {a_1}{r^2} + {a_1}{r^3} + ........................\infty \]
From equation (1)
\[ \Rightarrow {\text{2}}{a_1} = \dfrac{{{a_1}}}{{1 - r}}\]
Now it is given that \[{a_1} = 1\]
\[
\Rightarrow {\text{2}} \times {\text{1}} = \dfrac{1}{{1 - r}} \\
\Rightarrow 1 - r = \dfrac{1}{2} \Rightarrow r = 1 - \dfrac{1}{2} = \dfrac{1}{2} \\
\]
So the required is
\[
{a_1},{\text{ }}{a_1}r,{\text{ }}{a_1}{r^2}{\text{, }}{a_1}{r^3}{\text{, }}........................\infty \\
= 1,{\text{ }}\dfrac{1}{2}{\text{, }}{\left( {\dfrac{1}{2}} \right)^2}{\text{, }}{\left( {\dfrac{1}{2}} \right)^3}{\text{, }}{\left( {\dfrac{1}{2}} \right)^4}{\text{, }}.......................... \\
\]
So, this is the required answer.
Note: - In these types of questions the key concept is that always remember the sum of infinite terms G.P and the general series of infinite G.P, then according to given conditions calculate the value of common ratio, after getting this we can easily calculate the required infinite terms G.P series.
It is given that the first term of an infinite G.P is 1.
\[ \Rightarrow {a_1} = 1\]
Now, we know the sum of infinite G.P \[\left( {{S_\infty }} \right) = \dfrac{{{a_1}}}{{1 - r}}\], (where r is the common ratio)
Let the infinite G.P series is
\[{a_1},{\text{ }}{a_1}r,{\text{ }}{a_1}{r^2}{\text{, }}{a_1}{r^3}{\text{, }}........................\infty \]
Therefore the sum of this series is
\[{S_\infty } = {a_1} + {a_1}r + {a_1}{r^2} + {a_1}{r^3} + ........................\infty = \dfrac{{{a_1}}}{{1 - r}}................\left( 1 \right)\]
Now according to question it is given that any term is equal to the sum of succeeding terms
\[ \Rightarrow {a_1} = {a_1}r + {a_1}{r^2} + {a_1}{r^3} + ........................\infty \]
Now add both sides by \[{a_1}\]
\[ \Rightarrow {a_1} + {a_1} = {a_1} + {a_1}r + {a_1}{r^2} + {a_1}{r^3} + ........................\infty \]
From equation (1)
\[ \Rightarrow {\text{2}}{a_1} = \dfrac{{{a_1}}}{{1 - r}}\]
Now it is given that \[{a_1} = 1\]
\[
\Rightarrow {\text{2}} \times {\text{1}} = \dfrac{1}{{1 - r}} \\
\Rightarrow 1 - r = \dfrac{1}{2} \Rightarrow r = 1 - \dfrac{1}{2} = \dfrac{1}{2} \\
\]
So the required is
\[
{a_1},{\text{ }}{a_1}r,{\text{ }}{a_1}{r^2}{\text{, }}{a_1}{r^3}{\text{, }}........................\infty \\
= 1,{\text{ }}\dfrac{1}{2}{\text{, }}{\left( {\dfrac{1}{2}} \right)^2}{\text{, }}{\left( {\dfrac{1}{2}} \right)^3}{\text{, }}{\left( {\dfrac{1}{2}} \right)^4}{\text{, }}.......................... \\
\]
So, this is the required answer.
Note: - In these types of questions the key concept is that always remember the sum of infinite terms G.P and the general series of infinite G.P, then according to given conditions calculate the value of common ratio, after getting this we can easily calculate the required infinite terms G.P series.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Two charges are placed at a certain distance apart class 12 physics CBSE
Difference Between Plant Cell and Animal Cell
What organs are located on the left side of your body class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The planet nearest to earth is A Mercury B Venus C class 6 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
What is BLO What is the full form of BLO class 8 social science CBSE