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# The equivalent conductance at infinite dilution of $\text{HCl }$ and $\text{NaCl}$ are 426.15 and 126.15 $\text{mhoc}{{\text{m}}^{2}}\text{g e}{{\text{q}}^{-1}}$ respectively. It can be said that the mobility of:A. ${{\text{H}}^{+}}$ ions is much more than that of $\text{C}{{\text{l}}^{-}}$ ions.B. $\text{C}{{\text{l}}^{-}}$ ions is much more than that of ${{\text{H}}^{+}}$ ions.C. ${{\text{H}}^{+}}$ ions is much more than that of $\text{N}{{\text{a}}^{+}}$ ions.D. $\text{N}{{\text{a}}^{+}}$ ions is much more than that of${{\text{H}}^{+}}$ ions.

- It is given in the question, that the molar conductance of $\text{HCl }$ and $\text{NaCl}$ are 426.15 and 126.15 $\text{mhoc}{{\text{m}}^{2}}\text{g e}{{\text{q}}^{-1}}$ respectively which means hydrochloric acid has the higher value than sodium chloride.
- Here, between $\text{HCl }$and $\text{NaCl}$, the $\text{C}{{\text{l}}^{1-}}$ is a common ion so we will neglect the mobility of chlorine ion.
- So, between ${{\text{H}}^{+}}$ and $\text{N}{{\text{a}}^{+}}$, ${{\text{H}}^{+}}$ ions have a higher value of equivalent conductance.
- It indicates the higher mobility of ${{\text{H}}^{+}}$ions than the sodium ions.