Question

The element with atomic number 118 will be –
A.Alkali
B.Noble Gas
C.Lanthanide
D. Transition element

Answer 1

Hint: We know that the elements with different atomic numbers have a different electronic configuration which enables us to understand the positions of these elements in the periodic table. A periodic table contains elements which are grouped in different blocks \[\left( s,\text{ }p,\text{ }d,f \right)\]

Complete answer:
First of all let us understand what an atomic number and electronic configuration is; Atomic number of an element of a chemical element is the number of electrons present in the neutral species. Electrons of an atom or molecule distribute itself in atomic or molecular orbital. This distribution refers to electronic configuration. Electronic configuration provides insight into the chemical behavior of elements and also the position of the elements in the periodic table.
Also while solving or even while identifying we should consider some properties i.e. chemical properties:
Characteristics of noble gases are odorless, non-flammable, colorless, and monoatomic gas with low chemical reactivity.
All the noble gases conduct electricity and fluorescence which can be needed in many conditions to maintain a constant and safe environment.
All noble gases are insoluble in water.
As they have a complete octet which makes them highly stable. So, they hardly react with other elements to form chemical bonds because of their fewer tendencies to either gain or lose electrons. But as exceptions are everywhere. $Xe$ is the exception in this case. Xenon is the noble gas that may form compounds either with fluoride or oxide
Further the important steps for determining electronic configuration we
Shells: Electronic configuration of an element with atomic number will be $\left[ Rn \right]5{{f}^{14}}6{{d}^{16}}7{{s}^{2}}7{{p}^{6}}$.
Subshells: its electronic configuration in the outermost orbit $\left( n{{s}^{2}}n{{p}^{6}} \right)$
Notations: This resembles that of inert or noble gases such as Argon $\left[ Ne \right]3{{s}^{2}}3{{p}^{6}}$.

Thus, it will be a noble gas element. Therefore, option (B) is the correct option i.e. Noble Gas.

Note: Note that we also analyze and solve the question by considering Radon which is noble gas, also which has atomic number $86$ When $32$ electrons are added to it, we get the element with atomic number $118$ Since, in the seventh period, a maximum of $32$ electrons can be accommodated; Hence, element with atomic number $118$ is a noble gas.