
The electrophilic aromatic substitution proceeds through a:
A. Free radical
B. sigma complex
C. Benzyne
D. Carbene
Answer
580.8k+ views
Hint: Electrophilic aromatic substitution reaction is those in which the electrophile is responsible for the replacement of the atom from the aromatic ring. During the reaction, the formation of the sigma bond takes place.
Complete answer:
-An electrophile is a positively charged particle which can accept the electron pair.
-The action of electrophile is that it makes bonds in the reaction by accepting a pair of electrons from the reacting species.
-In this type of reaction, firstly the electrophile which has a positive charge attack on the $\pi $-bond of the aromatic ring forms carbocation.
-Now, the structure is stabilised with the help of resonance of the single electron that is left.
-Because one after breaking the bond one electron was accepted by the electrophile to make a sigma bond.
-And hence, the formation of the sigma bond takes place.
-The cation formed due to the action of an electrophile is known as sigma complex, named due to the formation of a sigma bond.
-The sigma bond may regain the properties of the aromatic ring by either losing the proton form the benzene ring or by reversing the first step that is the generation of a carbocation.
So, the correct answer is “Option B”.
Note: Free radicals are the atoms of molecules which consist of unpaired valence electrons which are highly reactive and make bonds easily. Whereas benzyne is also a reactive intermediate that is formed in the elimination reaction. A carbene is an electrophile which has two unshared valence electrons.
Complete answer:
-An electrophile is a positively charged particle which can accept the electron pair.
-The action of electrophile is that it makes bonds in the reaction by accepting a pair of electrons from the reacting species.
-In this type of reaction, firstly the electrophile which has a positive charge attack on the $\pi $-bond of the aromatic ring forms carbocation.
-Now, the structure is stabilised with the help of resonance of the single electron that is left.
-Because one after breaking the bond one electron was accepted by the electrophile to make a sigma bond.
-And hence, the formation of the sigma bond takes place.
-The cation formed due to the action of an electrophile is known as sigma complex, named due to the formation of a sigma bond.
-The sigma bond may regain the properties of the aromatic ring by either losing the proton form the benzene ring or by reversing the first step that is the generation of a carbocation.
So, the correct answer is “Option B”.
Note: Free radicals are the atoms of molecules which consist of unpaired valence electrons which are highly reactive and make bonds easily. Whereas benzyne is also a reactive intermediate that is formed in the elimination reaction. A carbene is an electrophile which has two unshared valence electrons.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Bacterial cell wall is made up of A Cellulose B Hemicellulose class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

