The domain of the function
$f(x) = \dfrac{1}{{\sqrt {\left| x \right| - x} }}$ is
$
A.( - \infty ,\infty ) \\
B.(0,\infty ) \\
C.( - \infty ,0) \\
D.( - \infty , - \infty ) - \{ 0\} \\
$
Answer
617.7k+ views
Hint:This is a simple question based on function and its domain set and codomain set. As we know that domain is the set of all the values that go into a function. We will find the set of possible values which will satisfy the given function.
Complete step-by-step answer:
Given function is:
$f(x) = \dfrac{1}{{\sqrt {\left| x \right| - x} }}$
It is a modulus function in its denominator under the square root.
This function will be defined only for the non-zero value of the denominator.
It means, $
\sqrt {\left| x \right| - x} > 0 \\
\\
$
Which further shows that, $\left| x \right| - x > 0$
$ \Rightarrow \left| x \right| > x$
The above expression will be valid only for the negative values of variable x. Also for the positive values it will be invalid.
Thus, the domain of function will be $( - \infty ,0)$. Here the set must be open on both sides.
So, the correct answer is “Option C”.
Note:While introducing the functions in mathematics, we have to define its formula with the possible set of values for domain and range values. The function is for representing the relationship between domain and codomain sets. This relation will be valid for some specific domain. This domain will be the set of valid points. This function is also termed as mapping. The domain of a function may be represented along the x axis and its range values can be represented along the y-axis.
Complete step-by-step answer:
Given function is:
$f(x) = \dfrac{1}{{\sqrt {\left| x \right| - x} }}$
It is a modulus function in its denominator under the square root.
This function will be defined only for the non-zero value of the denominator.
It means, $
\sqrt {\left| x \right| - x} > 0 \\
\\
$
Which further shows that, $\left| x \right| - x > 0$
$ \Rightarrow \left| x \right| > x$
The above expression will be valid only for the negative values of variable x. Also for the positive values it will be invalid.
Thus, the domain of function will be $( - \infty ,0)$. Here the set must be open on both sides.
So, the correct answer is “Option C”.
Note:While introducing the functions in mathematics, we have to define its formula with the possible set of values for domain and range values. The function is for representing the relationship between domain and codomain sets. This relation will be valid for some specific domain. This domain will be the set of valid points. This function is also termed as mapping. The domain of a function may be represented along the x axis and its range values can be represented along the y-axis.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Which gas is abundant in air class 11 chemistry CBSE

10 examples of friction in our daily life

