
The density of a DNA sample is 1.1 g/ml and its molar mass determined by the cryoscopic method was found to be $\text{6 }\times \text{ 1}{{\text{0}}^{8}}\text{gmole}$. What is the volume occupied by one DNA molecule? $\text{(}{{\text{N}}_{\text{A}}}\text{ = 6 }\times \text{ 1}{{\text{0}}^{23}})$
A. $\text{5}\text{.45 }\times \text{ 1}{{\text{0}}^{8}}\text{ ml}$
B. $\text{1}\text{.83 }\times \text{ 1}{{\text{0}}^{-9}}\text{ ml}$
C. $\text{9}\text{.06 }\times \text{ 1}{{\text{0}}^{-16}}\text{ ml}$
D. $\text{1}\text{.09 }\times \text{ 1}{{\text{0}}^{-13}}\text{ ml}$
Answer
578.7k+ views
Hint: Density of a substance is defined as the ratio of mass by volume which has a unit of kilogram per cubic metre. Density is denoted by $\rho $. The formula to calculate no. of the molecule is $\dfrac{\text{No}\text{. of molecules}}{{{\text{N}}_{\text{A}}}}\text{ = }\dfrac{\text{Mass}}{\text{Molar mass}}$. Here, ${{\text{N}}_{\text{A}}}$ is the Avogadro's number and mass is the mass of the DNA which is to be calculated and Molar mass of the DNA is also given in the question.
Complete answer:
-It is given in the question that the density of the DNA is 1.1 g/mol and we have to calculate the volume that is occupied by One DNA molecule.
-So, according to the formula of density, the mass of the DNA and volume should be needed.
-Now, we will calculate the mass of one DNA molecule first i.e.
$\dfrac{\text{No}\text{. of molecules}}{{{\text{N}}_{\text{A}}}}\text{ = }\dfrac{\text{Mass}}{\text{Molar mass}}$
$\text{Mass = }\dfrac{\text{No}\text{. of molecules }\times \text{ Molar mass}}{{{\text{N}}_{\text{A}}}}$
-Here, ${{\text{N}}_{\text{A}}}$ is called the Avogadro's number whose value is given in the question i.e. $\text{6 }\times \text{ 1}{{\text{0}}^{23}}$
$\text{Mass = }\dfrac{\text{1 }\times \text{ 6 }\times \text{ 1}{{\text{0}}^{8}}}{6\text{ }\times \text{ 1}{{\text{0}}^{23}}}$
$\text{Mass = 1}{{\text{0}}^{-15}}\text{gm}$
-Now, we know that the density of 1 molecule of DNA is 1.1 g/mol. So, the volume will be:
$\text{Volume = }\dfrac{\text{Mass}}{\text{Density}}$
$\text{Volume = }\dfrac{{{10}^{-15}}}{1.1}$
$\text{Volume = 0}\text{.906 }\times \text{ 1}{{\text{0}}^{-15}}\text{ml or 9}\text{.06 }\times \text{ 1}{{\text{0}}^{-16}}\text{ml}$
So, the correct answer is “Option C”.
Note: Cryoscopic method is the method which is used to determine the process of unknown molecular weight of a substance with the help of cryoscopic constant that is denoted by ${{\text{K}}_{\text{f}}}$. Moreover, it gives the relationship between the freezing point and molality (Ratio of no. of a mole of solute to the volume of solvent in Kg).
Complete answer:
-It is given in the question that the density of the DNA is 1.1 g/mol and we have to calculate the volume that is occupied by One DNA molecule.
-So, according to the formula of density, the mass of the DNA and volume should be needed.
-Now, we will calculate the mass of one DNA molecule first i.e.
$\dfrac{\text{No}\text{. of molecules}}{{{\text{N}}_{\text{A}}}}\text{ = }\dfrac{\text{Mass}}{\text{Molar mass}}$
$\text{Mass = }\dfrac{\text{No}\text{. of molecules }\times \text{ Molar mass}}{{{\text{N}}_{\text{A}}}}$
-Here, ${{\text{N}}_{\text{A}}}$ is called the Avogadro's number whose value is given in the question i.e. $\text{6 }\times \text{ 1}{{\text{0}}^{23}}$
$\text{Mass = }\dfrac{\text{1 }\times \text{ 6 }\times \text{ 1}{{\text{0}}^{8}}}{6\text{ }\times \text{ 1}{{\text{0}}^{23}}}$
$\text{Mass = 1}{{\text{0}}^{-15}}\text{gm}$
-Now, we know that the density of 1 molecule of DNA is 1.1 g/mol. So, the volume will be:
$\text{Volume = }\dfrac{\text{Mass}}{\text{Density}}$
$\text{Volume = }\dfrac{{{10}^{-15}}}{1.1}$
$\text{Volume = 0}\text{.906 }\times \text{ 1}{{\text{0}}^{-15}}\text{ml or 9}\text{.06 }\times \text{ 1}{{\text{0}}^{-16}}\text{ml}$
So, the correct answer is “Option C”.
Note: Cryoscopic method is the method which is used to determine the process of unknown molecular weight of a substance with the help of cryoscopic constant that is denoted by ${{\text{K}}_{\text{f}}}$. Moreover, it gives the relationship between the freezing point and molality (Ratio of no. of a mole of solute to the volume of solvent in Kg).
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

