Question

The bond order of individual carbon- carbon bonds in benzene is:
A ) one
B ) two
C ) between one and two
D) one and two alternately

Answer 1

Hint: In this question we have to find the bond order of carbon - carbon bonds which are present in benzene. So bond order is the number of bonding pairs of electrons between the two atoms .By using the concept of hybridisation we can calculate the bond order of benzene.

Complete step by step answer:
Benzene is a resonance hybrid of two resonating structures. Bond order of benzene can be calculated as the number of resonating bonds divided by the number of resonating structures .
Therefore,
Bond order $ = \dfrac{{{\text{number of resonating bonds}}}}{{{\text{number of resonating structures}}}}$
$ = \dfrac{{\text{3}}}{{\text{2}}}$
${\text{ = 1}}{\text{.5}}$
So, the bond order of individual carbon -carbon bonds is between one and two. It is due to the resonance structure of benzene. As we know in this compound, ${\text{6}}$ Pi electrons are shared by ${\text{6}}$ carbon atoms and every carbon has half a Pi bond one sigma bond.

So, the correct answer is Option C.

Note:
As if there are two or more than two atoms in the molecule ,then calculate the bond order so do the following steps :-
Firstly draw the Lewis structure.
Count the total number of bonds.
Count the number of bond groups between individual atoms.
Divide the number of bonds between atoms by the total number of bond groups in the molecule.
The bond order formula is defined as the number of chemical bonds between a pair of atoms and it also indicates the stability of a bond. As bond order increases across a period and decreases down a group.