Answer
405.3k+ views
Hint: Bond order is introduced by Linus Pauling . The bond number itself is that the number of electron pairs (bonds) between a pair of atoms. Bond number gives a sign of the steadiness of a bond. Isoelectronic species have the same bond number.
Complete step by step answer:
If there are greater than two atoms within the molecule, follow these steps to see the bond order: -Draw the Lewis structure
-Count the entire number of bonds.
-Count the amount of bond groups between individual atoms.
-Divide the amount of bonds between atoms by the overall number of bond groups within the molecule. Bond order is defined as half the difference between the amount of electrons in bonding molecular orbital (Nb) and therefore the number of electrons within the antibonding molecular orbitals (${{N}_{a}}$). The bond order describes the steadiness of the bond. The molecular orbital provides a simple understanding of the concept of the bond order of an attraction. It gives us an approximate quantity of the degree of covalent bonds between the atoms. i.e., Bond order =$\dfrac{1}{2}({{N}_{b}}-{{N}_{a}})$
Here ${{N}_{b}}$ is the no of bonding electrons and ${{N}_{a}}$ is the no of antibonding electrons. Number of bonds during a molecule is additionally referred to as bond order.
So, we can conclude that bond order is half the difference number of electrons in bonding and antibonding orbitals.
So, we obtain our answer as option D.
Note: The length of the bond is decided by the quantity of bonded electrons (the bond order). The upper the bond order, the stronger the pull between the 2 atoms and also the shorter the bond length. The sum of the covalent radii between the two atoms gives us the approximate length of the bond.
Complete step by step answer:
If there are greater than two atoms within the molecule, follow these steps to see the bond order: -Draw the Lewis structure
-Count the entire number of bonds.
-Count the amount of bond groups between individual atoms.
-Divide the amount of bonds between atoms by the overall number of bond groups within the molecule. Bond order is defined as half the difference between the amount of electrons in bonding molecular orbital (Nb) and therefore the number of electrons within the antibonding molecular orbitals (${{N}_{a}}$). The bond order describes the steadiness of the bond. The molecular orbital provides a simple understanding of the concept of the bond order of an attraction. It gives us an approximate quantity of the degree of covalent bonds between the atoms. i.e., Bond order =$\dfrac{1}{2}({{N}_{b}}-{{N}_{a}})$
Here ${{N}_{b}}$ is the no of bonding electrons and ${{N}_{a}}$ is the no of antibonding electrons. Number of bonds during a molecule is additionally referred to as bond order.
So, we can conclude that bond order is half the difference number of electrons in bonding and antibonding orbitals.
So, we obtain our answer as option D.
Note: The length of the bond is decided by the quantity of bonded electrons (the bond order). The upper the bond order, the stronger the pull between the 2 atoms and also the shorter the bond length. The sum of the covalent radii between the two atoms gives us the approximate length of the bond.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)