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# The bob of a simple pendulum is imparted at a velocity $5\,m{s^{ - 1}}$ when it is at its mean position. To what maximum vertical height will it rise on reaching to its extreme position if $60\%$ of its energy is lost in overcoming friction of air?A. $5\,m$B. $0.5\,m$C. $0.25\,m$D. $1\,m$

Last updated date: 04th Aug 2024
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Hint: To solve this question we have to know about kinetic energy and potential energy. We know that, to speed up an item we need to apply power. To apply power, we need to tackle jobs. At the point when work is done on an article, energy is moved and the item moves with another consistent speed.

We know that, when it is at mean position it will have a kinetic energy of $0.5\,m{v^2}$.
So, kinetic energy is equal to $0.5 \times m \times 5 \times 5 = 12.5\,mJ$
$60\%$ of this kinetic is lost hence remaining is equal to $(40/100)12.5 \times m = 5m$.
Now, potential energy is equal to $mgh = 5 \times m$.
$h =\dfrac{5}{g} \\ \Rightarrow h= \dfrac{5}{10} \\ \therefore h= 0.5\,m \\$