Question

# The bleaching action of ${{\text{H}}_{\text{2}}}{{\text{O}}_{\text{2}}}$ is due to which one of the following reactions:A.$PbS{\text{ }} + {\text{ }}4{H_2}{O_2}{\text{ }} \to {\text{ }}PbS{O_4}{\text{ }} + {\text{ }}4{H_2}O$B.${H_2}{O_2}{\text{ }} \to {\text{ }}{H_2}O{\text{ }} + {\text{ }}[O]$C.${H_2}{O_2}{\text{ }} + {\text{ }}[O]{\text{ }} \to {\text{ }}{H_2}O{\text{ }} + {\text{ }}{O_2}$D.${H_2}{O_2}{\text{ }} + {\text{ }}{O_3}{\text{ }} \to {\text{ }}{H_2}O{\text{ }} + {\text{ }}2{O_2}$

The perhydroxyl anion (${\text{H}}{{\text{O}}_{\text{2}}}^{\text{ - }}$) is the active bleaching species.
${H_2}{O_2}{\text{ }} \to {\text{ }}{H_2}O{\text{ }} + {\text{ }}[O]$