
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude in 5s. In another 10s it will decreases to $\alpha $ times its original magnitude where $\alpha $ equals
A: 0.81
B: 0.729
C: 0.6
D: 0.7
Answer
568.8k+ views
Hint: Amplitude of a damped oscillator decreases exponentially. For this first calculate the amplitude of the damped oscillator when it decreases o.9 times at 5 sec. Similarly find the decrease in amplitude at 10s using the concept amplitude decreases exponentially. By comparing both the equations we will get the value of $\alpha $ .
Formula used:
$A={{A}_{0}}{{e}^{-kt}}$
where, A is the new amplitude.
${A_0}$ is the initial amplitude.
t is the time taken to decrease the amplitude.
k is the damping constant.
Complete answer:
The amplitude of oscillations gradually decreases to zero as a result of frictional forces, arising due to the viscosity of the medium in which the oscillator is moving. The motion of the oscillator is damped by friction and therefore is called a damped harmonic oscillator. .
If damping is taken into account then a harmonic oscillator experiences a restoring force and a damping force proportional to the velocity.
Then the equation of motion of the damped harmonic oscillator is given by,
$\dfrac{{{d}^{2}}x}{d{{t}^{2}}}=-\gamma \dfrac{dx}{dt}-Cx$
$\dfrac{{{d}^{2}}x}{d{{t}^{2}}}+\gamma \dfrac{dx}{dt}+Cx=0$
$\dfrac{{{d}^{2}}x}{d{{t}^{2}}}+2k\dfrac{dx}{dt}+{{\omega }_{0}}x=0$
where, $2k=\dfrac{\gamma }{m}$ and ${{\omega }_{0}}=\sqrt{\dfrac{C}{m}}$
Then amplitude A is,
$A={{A}_{0}}{{e}^{-kt}}$
substituting the values of amplitude, initial amplitude and time in the above equation we get,
0.9${A_0}$=${{A}_{0}}{{e}^{-5k}}$
$\Rightarrow $ 0.9=${{e}^{-5k}}$
Taking natural log on both sides,
$\Rightarrow $ ln(0.9)= -5k
At time t=15s equation becomes,
$A={{A}_{0}}{{e}^{-15k}}={{A}_{0}}{{e}^{3ln(0.9)}}$
= ${{A}_{0}}{{(0.9)}^{3}}=0.729{{A}_{_{0}}}$
Hence,option (B) is correct.
Additional information:
The frictional force, acting on a body opposite to the direction of its motion, is called damping force. Such a force reduces the velocity and the kinetic energy of the moving body and so it is also called retarding or dissipative force. Damped oscillations means a decrease in intensity of oscillations with time. The force of friction retards the motion so that the system does not oscillate indefinitely. The friction reduces the mechanical energy of the system, the motion is said to be damped and this damping reduces amplitude of the vibratory motion.
Note:
The damping lowers the natural frequency of the object and also reduces the magnitude of amplitude of the wave. Amplitude of a damped oscillator decreases exponentially That is, the thermal energy of the damping force is removed from the system Thus damped oscillations means a decrease in intensity of oscillations with time.
Formula used:
$A={{A}_{0}}{{e}^{-kt}}$
where, A is the new amplitude.
${A_0}$ is the initial amplitude.
t is the time taken to decrease the amplitude.
k is the damping constant.
Complete answer:
The amplitude of oscillations gradually decreases to zero as a result of frictional forces, arising due to the viscosity of the medium in which the oscillator is moving. The motion of the oscillator is damped by friction and therefore is called a damped harmonic oscillator. .
If damping is taken into account then a harmonic oscillator experiences a restoring force and a damping force proportional to the velocity.
Then the equation of motion of the damped harmonic oscillator is given by,
$\dfrac{{{d}^{2}}x}{d{{t}^{2}}}=-\gamma \dfrac{dx}{dt}-Cx$
$\dfrac{{{d}^{2}}x}{d{{t}^{2}}}+\gamma \dfrac{dx}{dt}+Cx=0$
$\dfrac{{{d}^{2}}x}{d{{t}^{2}}}+2k\dfrac{dx}{dt}+{{\omega }_{0}}x=0$
where, $2k=\dfrac{\gamma }{m}$ and ${{\omega }_{0}}=\sqrt{\dfrac{C}{m}}$
Then amplitude A is,
$A={{A}_{0}}{{e}^{-kt}}$
substituting the values of amplitude, initial amplitude and time in the above equation we get,
0.9${A_0}$=${{A}_{0}}{{e}^{-5k}}$
$\Rightarrow $ 0.9=${{e}^{-5k}}$
Taking natural log on both sides,
$\Rightarrow $ ln(0.9)= -5k
At time t=15s equation becomes,
$A={{A}_{0}}{{e}^{-15k}}={{A}_{0}}{{e}^{3ln(0.9)}}$
= ${{A}_{0}}{{(0.9)}^{3}}=0.729{{A}_{_{0}}}$
Hence,option (B) is correct.
Additional information:
The frictional force, acting on a body opposite to the direction of its motion, is called damping force. Such a force reduces the velocity and the kinetic energy of the moving body and so it is also called retarding or dissipative force. Damped oscillations means a decrease in intensity of oscillations with time. The force of friction retards the motion so that the system does not oscillate indefinitely. The friction reduces the mechanical energy of the system, the motion is said to be damped and this damping reduces amplitude of the vibratory motion.
Note:
The damping lowers the natural frequency of the object and also reduces the magnitude of amplitude of the wave. Amplitude of a damped oscillator decreases exponentially That is, the thermal energy of the damping force is removed from the system Thus damped oscillations means a decrease in intensity of oscillations with time.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

