
The amount of heat energy required to raise the temperature of 1g of Helium at NTP, from $T_1$K to $T_2$K is
$A)\;\dfrac{3}{8}{N_a}{k_B}\left( {{T_2} - {T_1}} \right)$
$B)\;\dfrac{3}{2}{N_a}{k_B}\left( {{T_2} - {T_1}} \right)$
$C)\;\dfrac{3}{4}{N_a}{k_B}\left( {{T_2} - {T_1}} \right)$
$D)\;\dfrac{3}{4}{N_a}{k_B}\left( {\dfrac{{{T_2}}}{{{T_1}}}} \right)$
Answer
525.9k+ views
Hint: Here, the term, specific heat is required. So, the specific heat is that amount of heat that raises to the temperature of 1g of the substance by one degree Celsius or one Kelvin.
Complete step by step answer:
Here, the volume of the gas remains constant, thus the amount of the heat required to raise the temperature of the gas.
The expression is:
\[\Delta Q = n{C_V}\Delta T\] --- (1)
Here, $\Delta $Q is the change in heat.
$C_V$ is the Specific heat at constant volume
n is the number of moles,
$\Delta $T is the change in Temperature
So, we know that Helium is the monatomic molecule so, the value of specific heat at constant volume is
${C_V} = \dfrac{3}{2}R$
Here, R is the Universal Gas Constant
Number of moles, n = $\dfrac{1}{4}$
Change in temperature,$\Delta $T = ($T_2$ - $T_1$ )
So, no we put the value of change in temperature, number of moles and the specific heat at constant volume in equation (1)
$\Delta Q = \dfrac{1}{4} \times \dfrac{3}{2} \times R \times \left( {{T_2} - {T_1}} \right)$
$\Delta Q = \dfrac{3}{8} \times R \times \left( {{T_2} - {T_1}} \right)$ -- (2)
Here, the given option is in the form of the Boltzmann constant, $k_B$ and in the Avogadro constant $N_a$
The product of the Boltzmann constant, kB and the Avogadro constant, Na is equal to the molar gas constant.
$R = {k_B}{N_a}$
So, we put the value of R in the equation (2)
$ \Rightarrow \Delta Q = \dfrac{3}{8} \times {k_B} \times {N_a} \times \left( {{T_2} - {T_1}} \right)$
So, the change in heat is $\dfrac{3}{8}{N_a}{k_B}\left( {{T_2} - {T_1}} \right)$
So, the option (A) is correct.
Note:
Here, the difference between the universal gas constant and gas constant is that universal gas constant is only significant for the ideal gas; instead the gas constant is significant for the real gas.
Complete step by step answer:
Here, the volume of the gas remains constant, thus the amount of the heat required to raise the temperature of the gas.
The expression is:
\[\Delta Q = n{C_V}\Delta T\] --- (1)
Here, $\Delta $Q is the change in heat.
$C_V$ is the Specific heat at constant volume
n is the number of moles,
$\Delta $T is the change in Temperature
So, we know that Helium is the monatomic molecule so, the value of specific heat at constant volume is
${C_V} = \dfrac{3}{2}R$
Here, R is the Universal Gas Constant
Number of moles, n = $\dfrac{1}{4}$
Change in temperature,$\Delta $T = ($T_2$ - $T_1$ )
So, no we put the value of change in temperature, number of moles and the specific heat at constant volume in equation (1)
$\Delta Q = \dfrac{1}{4} \times \dfrac{3}{2} \times R \times \left( {{T_2} - {T_1}} \right)$
$\Delta Q = \dfrac{3}{8} \times R \times \left( {{T_2} - {T_1}} \right)$ -- (2)
Here, the given option is in the form of the Boltzmann constant, $k_B$ and in the Avogadro constant $N_a$
The product of the Boltzmann constant, kB and the Avogadro constant, Na is equal to the molar gas constant.
$R = {k_B}{N_a}$
So, we put the value of R in the equation (2)
$ \Rightarrow \Delta Q = \dfrac{3}{8} \times {k_B} \times {N_a} \times \left( {{T_2} - {T_1}} \right)$
So, the change in heat is $\dfrac{3}{8}{N_a}{k_B}\left( {{T_2} - {T_1}} \right)$
So, the option (A) is correct.
Note:
Here, the difference between the universal gas constant and gas constant is that universal gas constant is only significant for the ideal gas; instead the gas constant is significant for the real gas.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Bacterial cell wall is made up of A Cellulose B Hemicellulose class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

State the principle of an ac generator and explain class 12 physics CBSE

