Statement: $BaB{r_2}$ in aqueous Solution gives yellow ppt with ${K_2}Cr{O_4}$ as well as with $AgN{O_3}$ .
If the given statement is true enter $1$ else $0$.
Answer
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Hint: Barium bromide is a basic salt that can react with Potassium dichromate and silver nitrate. It acts as a simple salt. Barium bromide is attached to a highly basic cation and will form a covalent salt.
Complete step by step answer:
Barium Bromide contains an alkaline earth metal which makes the salt basic in nature. It can react with potassium dichromate which is an acidic salt to form a yellow compound or precipitate. The reaction is shown below:
$BaB{r_2} + {K_2}Cr{O_4} \to BaCr{O_4} + KBr$
Here the barium chromate which is formed is the yellow precipitate. This reaction is not yet balanced. The potassium atoms are not balanced. We can see that the potassium atoms on the reactant side are more than on the product side. Therefore, by adding two molecules of potassium bromate the reaction will be balanced and will look like this:
$BaB{r_2} + {K_2}Cr{O_4} \to BaCr{O_4} + 2KBr$
Therefore, both the bromine and potassium atoms are balanced.
For the next part of the reaction, barium bromide reacts with silver nitrate. Therefore, we will get the reaction,
$BaB{r_2} + AgN{O_3} \to Ba{\left( {N{O_3}} \right)_2} + AgBr$
The products formed are barium nitrate and silver bromide. The yellow precipitate is formed by barium nitrate. The bromine and nitrite ions are not balanced. Therefore, we will balance the reaction by considering two atoms of silver bromide and two atoms of silver nitrate on the reactant side. The reaction will now look like this:
$BaB{r_2} + 2AgN{O_3} \to Ba{\left( {N{O_3}} \right)_2} + 2AgBr$
Therefore, we can conclude that barium bromide will form a yellow precipitate. This means that the statement mentioned in the question is true. Therefore, the answer to the question will be $1$.
Note: The barium bromide is a basic simple salt.
-The yellow precipitate is formed by barium chromate in the reaction with potassium chromate.
-The bromide salt also forms barium nitrate when it reacts with silver nitrate.
Complete step by step answer:
Barium Bromide contains an alkaline earth metal which makes the salt basic in nature. It can react with potassium dichromate which is an acidic salt to form a yellow compound or precipitate. The reaction is shown below:
$BaB{r_2} + {K_2}Cr{O_4} \to BaCr{O_4} + KBr$
Here the barium chromate which is formed is the yellow precipitate. This reaction is not yet balanced. The potassium atoms are not balanced. We can see that the potassium atoms on the reactant side are more than on the product side. Therefore, by adding two molecules of potassium bromate the reaction will be balanced and will look like this:
$BaB{r_2} + {K_2}Cr{O_4} \to BaCr{O_4} + 2KBr$
Therefore, both the bromine and potassium atoms are balanced.
For the next part of the reaction, barium bromide reacts with silver nitrate. Therefore, we will get the reaction,
$BaB{r_2} + AgN{O_3} \to Ba{\left( {N{O_3}} \right)_2} + AgBr$
The products formed are barium nitrate and silver bromide. The yellow precipitate is formed by barium nitrate. The bromine and nitrite ions are not balanced. Therefore, we will balance the reaction by considering two atoms of silver bromide and two atoms of silver nitrate on the reactant side. The reaction will now look like this:
$BaB{r_2} + 2AgN{O_3} \to Ba{\left( {N{O_3}} \right)_2} + 2AgBr$
Therefore, we can conclude that barium bromide will form a yellow precipitate. This means that the statement mentioned in the question is true. Therefore, the answer to the question will be $1$.
Note: The barium bromide is a basic simple salt.
-The yellow precipitate is formed by barium chromate in the reaction with potassium chromate.
-The bromide salt also forms barium nitrate when it reacts with silver nitrate.
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