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# How many S-O-S linkage(s) is/ are present in ${H_2}{S_3}{O_6}$?

Last updated date: 16th Apr 2024
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Hint: In these types of problems we must remember the number of outermost electrons present in the valence shell of a particular element.
In any element each shell can contain only a fixed number of electrons. The first shell can hold up to 2 electrons. The second shell can hold up to 8 (2 + 6) electrons. The third shell can hold up to 18 (2 + 6 + 10) and so on.
The general formula is that the nth shell can in principle hold up to $2({n^2})$ electrons.

We will first make the structure of ${H_2}{S_3}{O_6}$
$HO - \mathop S\limits_{\mathop \parallel \limits_0 }^{\mathop \parallel \limits^O } - S - \mathop S\limits_{\mathop \parallel \limits_0 }^{\mathop \parallel \limits^O } - OH$
So, from this structure we can make out that there is no S-O-S linkage present in the ${H_2}{S_3}{O_6}$