Answer
Verified
480k+ views
Hint: First cross multiply the given equation and take a variable that is ‘y’ in the question on one side and constant on the other side. Then cross check by putting the value of "y” back in the given equation.
Here we have to solve the following equation
\[\dfrac{3y+4}{2-6y}=\dfrac{-2}{5}\]
First of all, we will cross multiply the given equation. So, we will get,
\[\left( 3y+4 \right)\left( 5 \right)=\left( -2 \right)\left( 2-6y \right)\]
By simplifying the equation, we get,
\[15y+20=-4+12y\]
Now, we will take the terms containing ‘y’ to the left hand side (LHS) and constant terms to the right hand side (RHS).
So, we will get,
\[15y-12y=-4-20\]
By simplifying the above equation, we get,
\[\Rightarrow 3y=-24\]
By dividing by 3 on both sides, we get,
\[y=\dfrac{-24}{3}\]
Therefore we get y = - 8
Hence, y = -8 is the correct answer.
Note: Here, students must take special care of signs while cross multiplying. In questions involving one variable, students should always try to take variables on one side and constants to the other side. After obtaining the answer, the student can cross check the same by substituting y = - 8 in the question and checking if it satisfies the same.
We can cross check as follows:
We are given the equation
\[\dfrac{3y+4}{2-6y}=\dfrac{-2}{5}\]
Here, we have to prove that LHS = RHS.
Since, we have got y = - 8, therefore, to cross check the answer, we will put y = - 8 in left hand side (LHS) of the given equation, we get LHS as,
\[LHS=\dfrac{3\left( -8 \right)+4}{2-6\left( -8 \right)}\]
By simplifying the above expression, we get,
\[LHS=\dfrac{-24+4}{2+48}=-\dfrac{20}{50}\]
Therefore, we get
\[LHS=-\dfrac{2}{5}\]
which is equal to RHS.
So our answer is correct.
Here we have to solve the following equation
\[\dfrac{3y+4}{2-6y}=\dfrac{-2}{5}\]
First of all, we will cross multiply the given equation. So, we will get,
\[\left( 3y+4 \right)\left( 5 \right)=\left( -2 \right)\left( 2-6y \right)\]
By simplifying the equation, we get,
\[15y+20=-4+12y\]
Now, we will take the terms containing ‘y’ to the left hand side (LHS) and constant terms to the right hand side (RHS).
So, we will get,
\[15y-12y=-4-20\]
By simplifying the above equation, we get,
\[\Rightarrow 3y=-24\]
By dividing by 3 on both sides, we get,
\[y=\dfrac{-24}{3}\]
Therefore we get y = - 8
Hence, y = -8 is the correct answer.
Note: Here, students must take special care of signs while cross multiplying. In questions involving one variable, students should always try to take variables on one side and constants to the other side. After obtaining the answer, the student can cross check the same by substituting y = - 8 in the question and checking if it satisfies the same.
We can cross check as follows:
We are given the equation
\[\dfrac{3y+4}{2-6y}=\dfrac{-2}{5}\]
Here, we have to prove that LHS = RHS.
Since, we have got y = - 8, therefore, to cross check the answer, we will put y = - 8 in left hand side (LHS) of the given equation, we get LHS as,
\[LHS=\dfrac{3\left( -8 \right)+4}{2-6\left( -8 \right)}\]
By simplifying the above expression, we get,
\[LHS=\dfrac{-24+4}{2+48}=-\dfrac{20}{50}\]
Therefore, we get
\[LHS=-\dfrac{2}{5}\]
which is equal to RHS.
So our answer is correct.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Change the following sentences into negative and interrogative class 10 english CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Application to your principal for the character ce class 8 english CBSE
Write a letter to the principal requesting him to grant class 10 english CBSE