Courses
Courses for Kids
Free study material
Offline Centres
More
Store

How do you solve $\ln x-\ln \left( x+2 \right)=1$?

Last updated date: 04th Aug 2024
Total views: 389.7k
Views today: 8.89k
Verified
389.7k+ views
Hint: We will look at the definition of logarithmic function. Then we will look at the logarithmic quotient rule. We will use this rule to simplify the given expression. Then we will convert the logarithmic function into its exponential form. After that we will simplify the equation obtained and solve it for the variable $x$.

The logarithmic function is defined as the inverse of the exponential function. So, if we have the exponential function as $y={{a}^{x}}$ then its equivalent logarithmic function to this is given as ${{\log }_{a}}y=x$. For example, we have ${{3}^{3}}=27$. Using the concept given above, we can rewrite this expression in the logarithmic form as ${{\log }_{3}}27=3$.
The logarithmic quotient rule is given as
${{\log }_{b}}\left( \dfrac{x}{y} \right)={{\log }_{b}}x-{{\log }_{b}}y$
Using this rule, we can write the given expression as the following,
\begin{align} & \ln x-\ln \left( x+2 \right)=1 \\ & \therefore \ln \left( \dfrac{x}{x+2} \right)=1 \\ \end{align}
As we have seen above, if we have the exponential function as $y={{a}^{x}}$ then its equivalent logarithmic function to this is given as ${{\log }_{a}}y=x$. The base of the natural logarithm is $e$. So, we can convert the above equation in its exponential form as follows,
$\dfrac{x}{x+2}={{e}^{1}}$
Now, we will simplify the above equation and solve for the variable $x$ in the following manner,
\begin{align} & x=e\left( x+2 \right) \\ & \therefore x=ex+2e \\ \end{align}
Shifting the terms with the variable $x$ to one side of the equation, we get the following,
$x-ex=2e$
Taking $x$ common, we have
\begin{align} & x\left( 1-e \right)=2e \\ & \therefore x=\dfrac{2e}{1-e} \\ \end{align}
So, the solution of the given equation is $x=\dfrac{2e}{1-e}$.

Note:
We should be familiar with the logarithmic functions and exponential functions. The relation between these two functions is very useful in simplification and calculation. Like the logarithmic quotient rule, there are other rules like product rule, power rule, base switch rule etc. These rules are important for simplifying equations.