Sodium hydroxide + Hydrochloric acid
A. Sodium chloride + Water
B. Sodium chloride + Water + Heat
C. Water + Heat
D. Sodium + Heat
Answer
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Hint:Sodium hydroxide is a base, when it reacts with hydrochloric acid acid-base reaction will happen. The formula of sodium hydroxide and hydrochloric acid are, NaOH, HCl. Sodium hydroxide is a strong base, but hydrochloric acid is a strong acid.
Complete step by step solution:
In this reaction between Sodium hydroxide and hydrochloric acid, water salt will be formed. And in case of reaction between a strong acid and strong base heat generated as this reaction is exothermic. The enthalpy is about 57.kJ/mol. The reaction is shown below,
\[NaOH\,\, + \,\,HCl \to NaCl\,\, + {H_2}O\]
So, the product of this reaction is Sodium chloride + Water + Heat
So, the correct answer is B.
Additional information:
Sodium acetate is the sodium salt of acetic acid, which can be formed by the reaction of sodium hydroxide which is a base and acetic acid. They undergo an acid-base reaction and form salt and water. The reaction is shown below,
\[NaOH\, + C{H_3}COOH \to C{H_3}COONa + {H_2}O\]
The aqueous solution of aluminum chloride is a salt of the weak acid and strong hydrochloride salt, the reaction is shown below,
\[HCl\, + N{H_4}OH \to N{H_4}Cl + {H_2}O\]
When aluminum chloride salt is added to a water solvent. it partially dissociates and its cation on reacting releases hydrogen ions. Writing a balanced chemical reaction can specify it. This is called hydrolysis of salt.
Aluminum chloride on reacting with water results in the formation of aluminum hydroxide and hydrochloric acid. The chemical equation of the reaction is:
\[AlC{l_3} + 3{H_2}O \to Al{(OH)_3} \downarrow + 3HCl\]
Here, aluminum hydroxide is a weak base i.e. it partially dissociates in the solution and is sparingly soluble in water, and therefore it is in precipitate form. Hydrochloric acid is a strong acid and can completely dissociate into respective cation and anion, \[{H^ + }\] and \[C{l^ - }\] .
Note:
When ammonium hydroxide and sulfuric acid, water salt will be formed. In this reaction, no such heat is generated as ammonium hydroxide is a weak base. The reaction is shown below,
\[2N{H_4}OH\, + {H_2}S{O_4} \to {\left( {N{H_4}} \right)_2}S{O_4} + 2{H_2}O\]
In this reaction Ammonium sulfate and Water is formed.
Complete step by step solution:
In this reaction between Sodium hydroxide and hydrochloric acid, water salt will be formed. And in case of reaction between a strong acid and strong base heat generated as this reaction is exothermic. The enthalpy is about 57.kJ/mol. The reaction is shown below,
\[NaOH\,\, + \,\,HCl \to NaCl\,\, + {H_2}O\]
So, the product of this reaction is Sodium chloride + Water + Heat
So, the correct answer is B.
Additional information:
Sodium acetate is the sodium salt of acetic acid, which can be formed by the reaction of sodium hydroxide which is a base and acetic acid. They undergo an acid-base reaction and form salt and water. The reaction is shown below,
\[NaOH\, + C{H_3}COOH \to C{H_3}COONa + {H_2}O\]
The aqueous solution of aluminum chloride is a salt of the weak acid and strong hydrochloride salt, the reaction is shown below,
\[HCl\, + N{H_4}OH \to N{H_4}Cl + {H_2}O\]
When aluminum chloride salt is added to a water solvent. it partially dissociates and its cation on reacting releases hydrogen ions. Writing a balanced chemical reaction can specify it. This is called hydrolysis of salt.
Aluminum chloride on reacting with water results in the formation of aluminum hydroxide and hydrochloric acid. The chemical equation of the reaction is:
\[AlC{l_3} + 3{H_2}O \to Al{(OH)_3} \downarrow + 3HCl\]
Here, aluminum hydroxide is a weak base i.e. it partially dissociates in the solution and is sparingly soluble in water, and therefore it is in precipitate form. Hydrochloric acid is a strong acid and can completely dissociate into respective cation and anion, \[{H^ + }\] and \[C{l^ - }\] .
Note:
When ammonium hydroxide and sulfuric acid, water salt will be formed. In this reaction, no such heat is generated as ammonium hydroxide is a weak base. The reaction is shown below,
\[2N{H_4}OH\, + {H_2}S{O_4} \to {\left( {N{H_4}} \right)_2}S{O_4} + 2{H_2}O\]
In this reaction Ammonium sulfate and Water is formed.
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