Simply the expression $\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}}$ and elaborate the steps.
Answer
572.7k+ views
Hint:First step in simplifying the question is that any variable when divided by a fraction implies that the variable is multiplied by the reciprocal of the fraction. Next, we simplify the exponent of the numerator of the overall fraction by breaking the exponent into parts. The final step will be rearranging the expression.
Complete step by step solution:
As we know that the division of any number or any expression by a fraction equals to the
multiplication of the same expression by the reciprocal of the fraction. The expression in the question can be written as
$\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}} = {x^{\dfrac{3}{2}}} \times (\dfrac{2}{3}) =
\dfrac{{2{x^{\dfrac{3}{2}}}}}{3}$
Let us now simplify the variable part of the expression, that is ${x^{\dfrac{3}{2}}}$.
We know that, ${x^{\dfrac{1}{2}}} = \sqrt x $.
So, ${x^{\dfrac{3}{2}}} = {({x^{\dfrac{1}{2}}})^3} = {({x^3})^{\dfrac{1}{2}}} = \sqrt {{x^3}} $… (Let this be equation (i))
Now that we have simplified the numerator of the expression, let us put the value of equation (i) in the place of the variable to arrive at the final expression.
$\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}} = \dfrac{{2{x^{\dfrac{3}{2}}}}}{3} = \dfrac{{2\sqrt {{x^3}} }}{3}$
Note: In this question we may also simplify ${x^{\dfrac{3}{2}}} = {x^{\dfrac{1}{2} + 1}} = {x^{\dfrac{1}{2}}} \times x$. If we put this in the expression, we get $\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}} = \dfrac{{2{x^{\dfrac{1}{2}}} \times x}}{3}$. This can be further written as, $\dfrac{{2x\sqrt x }}{3}$. In these types of simplifications, it is all subjective to when one wants to stop simplifying. There are also types of expressions that cannot be simplified, but rearranged. Some questions can just be a mixture of both.
Complete step by step solution:
As we know that the division of any number or any expression by a fraction equals to the
multiplication of the same expression by the reciprocal of the fraction. The expression in the question can be written as
$\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}} = {x^{\dfrac{3}{2}}} \times (\dfrac{2}{3}) =
\dfrac{{2{x^{\dfrac{3}{2}}}}}{3}$
Let us now simplify the variable part of the expression, that is ${x^{\dfrac{3}{2}}}$.
We know that, ${x^{\dfrac{1}{2}}} = \sqrt x $.
So, ${x^{\dfrac{3}{2}}} = {({x^{\dfrac{1}{2}}})^3} = {({x^3})^{\dfrac{1}{2}}} = \sqrt {{x^3}} $… (Let this be equation (i))
Now that we have simplified the numerator of the expression, let us put the value of equation (i) in the place of the variable to arrive at the final expression.
$\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}} = \dfrac{{2{x^{\dfrac{3}{2}}}}}{3} = \dfrac{{2\sqrt {{x^3}} }}{3}$
Note: In this question we may also simplify ${x^{\dfrac{3}{2}}} = {x^{\dfrac{1}{2} + 1}} = {x^{\dfrac{1}{2}}} \times x$. If we put this in the expression, we get $\dfrac{{{x^{\dfrac{3}{2}}}}}{{\dfrac{3}{2}}} = \dfrac{{2{x^{\dfrac{1}{2}}} \times x}}{3}$. This can be further written as, $\dfrac{{2x\sqrt x }}{3}$. In these types of simplifications, it is all subjective to when one wants to stop simplifying. There are also types of expressions that cannot be simplified, but rearranged. Some questions can just be a mixture of both.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

