Answer
414.9k+ views
Hint: A photodiode is a semiconductor device that is used to convert light into an electrical current. The current is generated when photons or light quanta are absorbed in the photodiode is very small and is in the order of $\mu A$. The current in forward bias mode is in the order of $mA$.
Complete answer:
A Photodiode is nothing but a p-n junction diode with a transparent window to allow light to fall on the diode. It operates under reverse bias.
When light (photons) of energy greater than the energy gap (${{E}_{g}}$) of the semiconductor incident on the diode, then electron-hole pairs are generated due to the absorption of photons. The generation of electron-hole pairs takes place near the depletion region of the diode. Due to the electric field of the junction, electrons and holes split up before they recombine since the direction of the electric field is such that electrons reach n-side and holes reach p-side giving rise to an emf. When an external load is connected, current flows. The magnitude of the photocurrent is related to the intensity of incident light.
In forward bias current is of the order $mA$ and thus, the photocurrent cannot be observed. If a reverse bias is applied, it is easier to observe the change in the current with change in the light intensity because reverse current without light is in the order of $\mu A$, the change in reverse current due to light is also in the order of $\mu A$. That is why; it is operated in reverse bias.
Hence, option C is correct.
Note:
When light (photons) of energy greater than the energy gap (${{E}_{g}}$) of the semiconductor incident on the photodiode, then electron-hole pairs are generated due to the absorption of photons. To create an electron-hole pair, we spend some energy in the form of light or heat. When an electron and hole recombine the energy is released in the form of light (radiative recombination) or heat (non-radiative recombination) in validation of law of conservation of energy.
Complete answer:
A Photodiode is nothing but a p-n junction diode with a transparent window to allow light to fall on the diode. It operates under reverse bias.
![seo images](https://www.vedantu.com/question-sets/0a550cf8-b773-4eed-a461-d1245d965ab75484180473011133076.png)
When light (photons) of energy greater than the energy gap (${{E}_{g}}$) of the semiconductor incident on the diode, then electron-hole pairs are generated due to the absorption of photons. The generation of electron-hole pairs takes place near the depletion region of the diode. Due to the electric field of the junction, electrons and holes split up before they recombine since the direction of the electric field is such that electrons reach n-side and holes reach p-side giving rise to an emf. When an external load is connected, current flows. The magnitude of the photocurrent is related to the intensity of incident light.
In forward bias current is of the order $mA$ and thus, the photocurrent cannot be observed. If a reverse bias is applied, it is easier to observe the change in the current with change in the light intensity because reverse current without light is in the order of $\mu A$, the change in reverse current due to light is also in the order of $\mu A$. That is why; it is operated in reverse bias.
Hence, option C is correct.
Note:
When light (photons) of energy greater than the energy gap (${{E}_{g}}$) of the semiconductor incident on the photodiode, then electron-hole pairs are generated due to the absorption of photons. To create an electron-hole pair, we spend some energy in the form of light or heat. When an electron and hole recombine the energy is released in the form of light (radiative recombination) or heat (non-radiative recombination) in validation of law of conservation of energy.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)