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# How many protons are found in an atom of platinum?

Last updated date: 02nd Aug 2024
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Answer
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Hint: For calculating the number of protons in an atom we have to see about the atomic number of that atom, because Atomic number $\left( Z \right)$ of an atom is always equal to the number of protons existing inside the nucleus or number of electrons present outer the nucleus in the orbitals.

Complete step by step answer:
Platinum is a compound element with the appearance $Pt$ and atomic number ${^{78}_{195}}Pt$. It is a thick, moldable, bendable, profoundly lifeless, valuable, silverish-white progress metal. Its name is gotten from the Spanish expression platino, signifying "minimal silver".
Platinum is situated in the Groups $8-10{\text{ }}\left( {VIIIb} \right)$, Periods $\;5$ and $6$, of the periodic table and denoted by the symbol as ${^{78}_{195}}Pt$.
-Upper quantity in ${^{78}_{195}}Pt$ describes the atomic number $\left( Z \right)$ of the platinum atom.
-Lower quantity in ${^{78}_{195}}Pt$ describes the atomic mass $\left( A \right)$ of the platinum atom.
As we see that relative between the atomic number and number of protons present inside the nucleus is denoted as follow:
Atomic Number $\left( Z \right)$ = No. of protons = No. of electrons
-From the denotation of platinum it is clear that the atomic number of platinum is $\;78$, so the number of protons in the platinum atom is also $\;78$ . Hence, in the nucleus of one atom of platinum $\;78$ protons are found.

Additional information:
Number of protons present inside the nucleus in an atom is also calculated by knowing the atomic mass $\left( A \right)$ and number of neutrons as follow atomic mass $\left( A \right)$ and number of neutrons as follow:
Atomic mass $\left( A \right)$ = No. of protons +No. of neutrons.

Note:
Here some of you may get disorganized on conniving the number of protons if atomic mass $\left( A \right)$ and atomic number $\left( Z \right)$ both are given, then in this situation always keep in mind that atomic number is equal to the number of protons.