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Hint: Chlorobenzene is reacted with sodium hydroxide to form a phenoxide ion. This is treated with dilute HCl. There is the formation of two intermediates during the mechanism. One of which is highly reactive and unstable and this soon gets attacked by OH- to form the send intermediate which finally gives phenol.
Complete answer: Dow’s process is a process of preparation of phenol from chlorobenzene. During the process, the chlorobenzene reacts with an aqueous solution of NaOH at a temperature of \[{350^0}C\] and a pressure of \[150\] atmospheres. This produces sodium phenoxide ions. After this, the sodium phenoxide ion is treated with dilute HCl which finally gives phenol. The reaction gives rise to a formation of benzyne intermediate.
The above reaction can also be referred to as hydrolysis of chlorobenzene. The reaction taking place here is electrophilic-aromatic substitution. The preparation of phenol from chlorobenzene takes place through the following mechanism:
In the above mechanism, there is the removal of a proton from carbon adjacent to the carbon bonded to chlorine by the base in the first step. This leads to the formation of carbanion. Then, chlorine ions will leave the benzene ring to form a triple bond in the benzene ring. This is the intermediate form called benzyne intermediate. This intermediate is short-lived. It is very unstable and highly reactive. So in the second step, this is attacked by nucleophile OH- to form another intermediate phenoxide ion. Now in the final step, this phenoxide ion undergoes acidification and finally gives phenol.
Therefore in the following way phenol is prepared from chlorobenzene by Dow’s process.
Note:
It is important to note that there is no direct substitution happening in chlorine. First, the chlorine gets removed then intermediate forms, and then finally phenol is produced. The reaction occurring above is via the elimination-addition mechanism which involves a benzyne intermediate. Dow’s process is also an electrolytic method for the extraction of bromine from brine.
Complete answer: Dow’s process is a process of preparation of phenol from chlorobenzene. During the process, the chlorobenzene reacts with an aqueous solution of NaOH at a temperature of \[{350^0}C\] and a pressure of \[150\] atmospheres. This produces sodium phenoxide ions. After this, the sodium phenoxide ion is treated with dilute HCl which finally gives phenol. The reaction gives rise to a formation of benzyne intermediate.
The above reaction can also be referred to as hydrolysis of chlorobenzene. The reaction taking place here is electrophilic-aromatic substitution. The preparation of phenol from chlorobenzene takes place through the following mechanism:
In the above mechanism, there is the removal of a proton from carbon adjacent to the carbon bonded to chlorine by the base in the first step. This leads to the formation of carbanion. Then, chlorine ions will leave the benzene ring to form a triple bond in the benzene ring. This is the intermediate form called benzyne intermediate. This intermediate is short-lived. It is very unstable and highly reactive. So in the second step, this is attacked by nucleophile OH- to form another intermediate phenoxide ion. Now in the final step, this phenoxide ion undergoes acidification and finally gives phenol.
Therefore in the following way phenol is prepared from chlorobenzene by Dow’s process.
Note:
It is important to note that there is no direct substitution happening in chlorine. First, the chlorine gets removed then intermediate forms, and then finally phenol is produced. The reaction occurring above is via the elimination-addition mechanism which involves a benzyne intermediate. Dow’s process is also an electrolytic method for the extraction of bromine from brine.
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