
Phenol does not decompose \[{\text{NaHC}}{{\text{O}}_{\text{3}}}\] to evolve \[{\text{C}}{{\text{O}}_{\text{2}}}\]but picric acid does.
A. True
B. False
Answer
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Hint: Sodium bicarbonate (\[{\text{NaHC}}{{\text{O}}_{\text{3}}}\]) is a weak base. In presence of acid \[{\text{NaHC}}{{\text{O}}_{\text{3}}}\] dissociate and liberate \[{\text{C}}{{\text{O}}_{\text{2}}}\]gas. Draw the structures of both phenol and picric acid and determine their acid strength.
Complete step by step answer:
Sodium bicarbonate (\[{\text{NaHC}}{{\text{O}}_{\text{3}}}\]) is a weak base when it reacts with acid it is converted into carbonic acid
(\[{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\]). As carbonic acid is unstable it dissociates into \[{\text{C}}{{\text{O}}_{\text{2}}}\]gas and water as follows:
\[{\text{NaHC}}{{\text{O}}_{\text{3}}}{\text{ + }}{{\text{H}}^{\text{ + }}}{\text{ }} \to {{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} \to {\text{C}}{{\text{O}}_{\text{2}}} + {{\text{H}}_{\text{2}}}{\text{O}}\]
Now we will draw the structures of both phenol and picric acid and determine their acid strength as both are acidic in nature.
From the structure of phenol and picric acid we can say that picric acid is substituted phenol, there are three electron-withdrawing ${\text{ - N}}{{\text{O}}_{\text{2}}}$ groups bonded to the ring.
The acidic strength of substituted phenol is dependent on the nature of the substituent.
The electron-withdrawing group decreases the electron density of the phenol ring and stabilizes the negative charge and thus increases the acid strength.
In the case of the picric acid, the substituent is a nitro group (${\text{ - N}}{{\text{O}}_{\text{2}}}$ ). It is an electron-withdrawing group so picric acid is a stronger acid than phenol.
As phenol is weak acid it cannot react with \[{\text{NaHC}}{{\text{O}}_{\text{3}}}\] to evolve\[{\text{C}}{{\text{O}}_{\text{2}}}\].
However, picric acid is stronger acid which reacts with base as shown below:
Hence, the given statement is true i.e, option ‘A’ is the correct answer.
Note: Ring activating groups that are electron-donating groups, decrease the strength of acid while a ring deactivating group increases the strength of the acid. So while determining acid strength it is necessary to determine whether the substituent is an electron-donating group or electron-withdrawing group.
Complete step by step answer:
Sodium bicarbonate (\[{\text{NaHC}}{{\text{O}}_{\text{3}}}\]) is a weak base when it reacts with acid it is converted into carbonic acid
(\[{{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}}\]). As carbonic acid is unstable it dissociates into \[{\text{C}}{{\text{O}}_{\text{2}}}\]gas and water as follows:
\[{\text{NaHC}}{{\text{O}}_{\text{3}}}{\text{ + }}{{\text{H}}^{\text{ + }}}{\text{ }} \to {{\text{H}}_{\text{2}}}{\text{C}}{{\text{O}}_{\text{3}}} \to {\text{C}}{{\text{O}}_{\text{2}}} + {{\text{H}}_{\text{2}}}{\text{O}}\]
Now we will draw the structures of both phenol and picric acid and determine their acid strength as both are acidic in nature.


From the structure of phenol and picric acid we can say that picric acid is substituted phenol, there are three electron-withdrawing ${\text{ - N}}{{\text{O}}_{\text{2}}}$ groups bonded to the ring.
The acidic strength of substituted phenol is dependent on the nature of the substituent.
The electron-withdrawing group decreases the electron density of the phenol ring and stabilizes the negative charge and thus increases the acid strength.
In the case of the picric acid, the substituent is a nitro group (${\text{ - N}}{{\text{O}}_{\text{2}}}$ ). It is an electron-withdrawing group so picric acid is a stronger acid than phenol.
As phenol is weak acid it cannot react with \[{\text{NaHC}}{{\text{O}}_{\text{3}}}\] to evolve\[{\text{C}}{{\text{O}}_{\text{2}}}\].

However, picric acid is stronger acid which reacts with base as shown below:

Hence, the given statement is true i.e, option ‘A’ is the correct answer.
Note: Ring activating groups that are electron-donating groups, decrease the strength of acid while a ring deactivating group increases the strength of the acid. So while determining acid strength it is necessary to determine whether the substituent is an electron-donating group or electron-withdrawing group.
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