Oxidation number of carbon in $SC{{N}^{-}}$ ion is:
Answer
281.1k+ views
Hint: To find the oxidation number of the given element in the compound or ion we need to know the oxidation numbers of other elements so, the oxidation number of sulfur will be -2 and the oxidation number of nitrogen will be -3. Since it is a single negative ion, the sum of oxidation number of sulfur, carbon, and nitrogen will be equal to -1.
Complete answer:
The oxidation number, also known as the oxidation number, is a state of an element that is used to describe the property of the composition of a compound with other elements.
To find the oxidation number of the given element in the compound or ion we need to know the oxidation numbers of other elements so, the oxidation number of sulfur will be -2 and the oxidation number of nitrogen will be -3. Since it is a single negative ion, the sum of oxidation number of sulfur, carbon, and nitrogen will be equal to -1.
Let us take the oxidation number of carbon as x. Now putting the values, we get:
$-2+x-3=-1$
$x-5=-1$
$x=+5-1$
$x=+4$
So, the oxidation number of carbon in $SC{{N}^{-}}$ will be +4.
The structure of $SC{{N}^{-}}$ ion is given below:
There can be many equivalent structures of this compound because of resonance in the compound.
Note:
With the help of finding the number of groups of the element then we can easily find the oxidation number of the element like if the group is 16 then the oxidation number will be -2, i.e., oxygen and sulfur.
Complete answer:
The oxidation number, also known as the oxidation number, is a state of an element that is used to describe the property of the composition of a compound with other elements.
To find the oxidation number of the given element in the compound or ion we need to know the oxidation numbers of other elements so, the oxidation number of sulfur will be -2 and the oxidation number of nitrogen will be -3. Since it is a single negative ion, the sum of oxidation number of sulfur, carbon, and nitrogen will be equal to -1.
Let us take the oxidation number of carbon as x. Now putting the values, we get:
$-2+x-3=-1$
$x-5=-1$
$x=+5-1$
$x=+4$
So, the oxidation number of carbon in $SC{{N}^{-}}$ will be +4.
The structure of $SC{{N}^{-}}$ ion is given below:

There can be many equivalent structures of this compound because of resonance in the compound.
Note:
With the help of finding the number of groups of the element then we can easily find the oxidation number of the element like if the group is 16 then the oxidation number will be -2, i.e., oxygen and sulfur.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Which of the following would not be a valid reason class 11 biology CBSE

Why should electric field lines never cross each other class 12 physics CBSE

An electrostatic field line is a continuous curve That class 12 physics CBSE

What is meant by monosporic development of female class 11 biology CBSE

Draw labelled diagram of the following i Gram seed class 11 biology CBSE

Trending doubts
Change the following sentences into negative and interrogative class 10 english CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

What is 1 divided by 0 class 8 maths CBSE

Difference Between Plant Cell and Animal Cell

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Convert compound sentence to simple sentence He is class 10 english CBSE

India lies between latitudes and longitudes class 12 social science CBSE

Why are rivers important for the countrys economy class 12 social science CBSE

Distinguish between Khadar and Bhangar class 9 social science CBSE
