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Oxidation number of carbon in $C{{O}_{2}}$ is:

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Hint:We can solve this question after defining the term oxidation number and then we will discuss the relation between oxidation number and charge. Then we know that the total charge on a neutral compound is always equal to zero.

Complete answer:
We know that the total charge on a neutral compound is always equal to zero.
Oxidation state of carbon in $C{{O}_{2}}$
Oxidation state of oxygen in the given compound= -2
Let the oxidation state of carbon = x
Oxidation state of the central metal atom i.e. carbon=
\[\begin{align}
  & x+2(-2)=0 \\
 & x=+4 \\
\end{align}\]
Hence the oxidation state of central metal atom i.e. carbon is +4

Additional information:
 For the IUPAC naming of compounds there are certain rules to be followed and also, we should calculate the oxidation number on the central metal ion. The oxidation state while writing the IUPAC nomenclature will be written in roman numbers inside brackets. If more than one atom is present, suffixes like di, tri, tetra are used.

Note:
The chemical symbol is C for carbon and O for oxygen. The chemical symbol is used to represent an atom or an element. The chemical symbol of an element usually consists of one or two letters from the Latin alphabet and the first letter is always capital. There are many sources from which the symbols are derived, it includes Greek name of an element or German name etc. Sometimes a 3-letter symbol is also assigned to a new element which is a temporary symbol for the element.