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# Out of ${\text{C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}$ and ${\text{CuC}}{{\text{l}}_{\text{2}}}$, which is more stable and why? Verified
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Hint: As we know that in chemistry, periodic tables play a vital role. In the periodic table totally $118$ elements. In the periodic table there are totally $18$ columns and $7$ rows. The columns are called groups. Hence, $18$ groups in the periodic table. The rows are called as period. Hence, totally $7$ period in the table. Copper is one of the metallic elements in the periodic table. It is present in the first transition series.

We must remember that each element in the periodic table has a certain group and period. In that case copper is one of the elements in the period. The atomic number of copper is $29$ and the symbol of copper is ${\text{Cu}}$. The mass number of copper is $63.5$.
The general electronic configuration of copper in ground state is ${\text{1}}{{\text{s}}^{\text{2}}}{\text{,2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{d}}^{\text{9}}}{\text{4}}{{\text{s}}^{\text{2}}}$ . Because of stability we can change the electronic configuration of copper is ${\text{1}}{{\text{s}}^{\text{2}}}{\text{,2}}{{\text{s}}^{\text{2}}}{\text{2}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{s}}^{\text{2}}}{\text{3}}{{\text{p}}^{\text{6}}}{\text{3}}{{\text{d}}^{10}}{\text{4}}{{\text{s}}^1}$.
Out of ${\text{C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}$ and ${\text{CuC}}{{\text{l}}_{\text{2}}}$, ${\text{CuC}}{{\text{l}}_{\text{2}}}$ is more stable than ${\text{C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}$. Because the oxidation of copper in ${\text{CuC}}{{\text{l}}_{\text{2}}}$ is ${\text{C}}{{\text{u}}^{{\text{ + 2}}}}$. But the oxidation state of copper in ${\text{C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}$ is ${\text{C}}{{\text{u}}^{{\text{ + 1}}}}$.
Copper has two oxidation states. There are ${\text{C}}{{\text{u}}^{{\text{ + 2}}}}$ and ${\text{C}}{{\text{u}}^{{\text{ + 1}}}}$ . The stability wise ${\text{C}}{{\text{u}}^{{\text{ + 2}}}}$ is more stable than ${\text{C}}{{\text{u}}^{{\text{ + 1}}}}$. That the reason ${\text{CuC}}{{\text{l}}_{\text{2}}}$ is more stable than ${\text{C}}{{\text{u}}_{\text{2}}}{\text{C}}{{\text{l}}_{\text{2}}}$.