Courses
Courses for Kids
Free study material
Offline Centres
More
Store

# Number of solutions of equation $\sin 9\theta =\sin \theta$ in the interval $\left[ 0,2\pi \right]$ is?

Last updated date: 13th Jul 2024
Total views: 346.8k
Views today: 6.46k
Verified
346.8k+ views
Hint: In the given question, we are given an equation in which we need to find the number of solutions. So, as we need to find the number of solutions, it is clear that the given equation has more than one solution. We will make use of some trigonometric identities in order to solve it.

According to the question, we are given an equation $\sin 9\theta =\sin \theta$and also given that $\theta$ lies in the interval $\left[ 0,2\pi \right]$. Therefore, it is clear that the solution would lie in the interval $\left[ 0,2\pi \right]$.
Now, let us consider the equation $\sin 9\theta =\sin \theta$ as below:
\begin{align} & \sin 9\theta =\sin \theta \\ & \Rightarrow \sin 9\theta -\sin \theta =0 \\ \end{align}
Now, making use of the trigonometric identity which is $\sin C-\sin D=2\cos \left( \dfrac{C+D}{2} \right)\sin \left( \dfrac{C-D}{2} \right)$
Now, our expression on left-hand side would be
\begin{align} & \sin 9\theta -\sin \theta =2\cos \left( \dfrac{9\theta +\theta }{2} \right)\sin \left( \dfrac{9\theta -\theta }{2} \right) \\ & \Rightarrow 2\cos 5\theta \sin 4\theta \\ \end{align}
Now, we need to equate the left-hand side of the expression to 0.
Now, here $\cos 5\theta =0$ and $\sin 4\theta =0$ .
Now,
\begin{align} & \Rightarrow \cos 5\theta =0 \\ & \therefore 5\theta =\left( 2n+1 \right)\dfrac{\pi }{2} \\ & \Rightarrow \theta =\left( 2n+1 \right)\dfrac{\pi }{10} \\ \end{align}
Now, taking n=0,1,2,3, … and now we need to substitute the values of n such that it doesn’t cross the interval.
Therefore, the values of $\theta$ are:
$\Rightarrow \dfrac{\pi }{10},\dfrac{3\pi }{10},\dfrac{5\pi }{10},\dfrac{7\pi }{10},\dfrac{9\pi }{10},\dfrac{11\pi }{10},\dfrac{13\pi }{10},\dfrac{15\pi }{10},\dfrac{17\pi }{10},\dfrac{19\pi }{10}$
So, here we get 10 values of theta.
Now,
\begin{align} & \Rightarrow \sin 4\theta =0 \\ & \therefore 4\theta =n\pi \\ & \Rightarrow \theta =\dfrac{n\pi }{4} \\ \end{align}
Now, we can take all values of theta such that it does not cross the interval.
Therefore, the values of $\theta$ are:
$\Rightarrow \dfrac{\pi }{4},\dfrac{2\pi }{4},\dfrac{3\pi }{4},\dfrac{4\pi }{4},\dfrac{5\pi }{4},\dfrac{6\pi }{4},\dfrac{7\pi }{4},\dfrac{8\pi }{4}$
Therefore, by this there are 8 values of theta.
Therefore, total solutions of the given equation are 18.

Note: Now, the most important thing that we need to keep in mind is that we take the appropriate values of n and remember to check that theta taken is from the given interval or not. Sometimes, we forget to check the interval and randomly try to check the solution for every value of n.