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Number of covalent bonds present in $Ca{(OCl)_2}$ .

Answer
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Hint: For solving, this question we need to first understand the meaning of covalent bonds. We can define a covalent bond as a type of a molecular bond in which a chemical bond is formed by sharing of the electron pairs between different atoms.

Complete step by step answer:
As we know that, the electron pairs shared between atoms are known as bonding pairs or shared pairs. They possess a stable balance of attractive and repulsive forces between the atoms, when they share electrons. Such type of bonding between atoms is known as covalent bonding.
Here, we know that a covalent bond is formed by the interatomic linkage that is formed by the sharing of an electron pair between two atoms. The binding arises from the electrostatic attraction of their nuclei for the same number of electrons.
We know that we can write $Ca{(OCl)_2}$ as $Ca(OCl)Cl$ . On the basis of this we know that there are $C{a^{ - 2}}$ ion, an $OC{l^ - }$ ion and an $C{l^ - }$ ion.
So, from the structure we can see there is a covalent bond shared between O and Cl in the atom of $OC{l^ - }$ .
To check the number of covalent bonds we will draw the structure of $OC{l^ - }$.
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So, from the above structure diagram we can note that the given oxychloride compound has 2 covalent bonds in the molecule.

Note:
Here, an ionic bond is also shared between $C{a^{2 + }}$ , $C{l^ - }$ and $OC{l^ - }$. The transfer of electrons is referred to an ionic bond. These bonds are electrostatic in nature. It is formed by the attraction of positive and negative ions that lead to transfer of electrons. And charge separation in ionic bonds is more in comparison to covalent bonds.