Answer
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Hint: In this reaction benzene is reacted with concentrated nitric acid and concentrated sulphuric acid. Conc. sulphuric acid being strong donates a proton to nitric acid to form an ion which attaches to the benzene ring.
Complete step by step answer:
-First of all let us see what is meant by nitration of benzene.
A reaction where benzene (${C_6}{H_6}$) will react with concentrated nitric acid ($conc.HN{O_3}$) at 323-333K in the presence of concentrated sulphuric acid ($conc.{H_2}S{O_4}$) resulting in the formation of nitrobenzene is known as nitration of benzene.
-We will now talk about the mechanism of this reaction:
Step-1) The two strong acids: $conc.{H_2}S{O_4}$ and $conc.HN{O_3}$ react with each other to form a very strong electrophile called the nitronium ion. Nitric acid accepts a proton from sulphuric acid because sulphuric acid is a stronger acid.
Step-2) Now benzene will react with this positively charged nitronium ion (electrophile) and leads to the formation of an arenium ion (by breaking one of the N=O bonds).
Step-3) Finally the arenium ion loses a proton to a lewis base (to regain its aromaticity) and leads to the formation of our final product nitrobenzene (${C_6}{H_5}N{O_2}$).
Here we can see that we have replaced a hydrogen atom from the benzene ring with a strong electrophile (nitronium ion, $NO_2^ + $), and hence we can call nitration of benzene as an electrophilic substitution reaction.
So, the correct answer is “Option C”.
Note: An electrophile is an ion which is itself positively charged and gets attracted to electron rich atoms or molecules, while a nucleophile is an ion which itself is negatively charged and gets attracted to electron deficient atoms or compounds. So, in an electrophilic substitution reaction an electrophile replaces another electrophile.
Complete step by step answer:
-First of all let us see what is meant by nitration of benzene.
A reaction where benzene (${C_6}{H_6}$) will react with concentrated nitric acid ($conc.HN{O_3}$) at 323-333K in the presence of concentrated sulphuric acid ($conc.{H_2}S{O_4}$) resulting in the formation of nitrobenzene is known as nitration of benzene.
-We will now talk about the mechanism of this reaction:
Step-1) The two strong acids: $conc.{H_2}S{O_4}$ and $conc.HN{O_3}$ react with each other to form a very strong electrophile called the nitronium ion. Nitric acid accepts a proton from sulphuric acid because sulphuric acid is a stronger acid.
Step-2) Now benzene will react with this positively charged nitronium ion (electrophile) and leads to the formation of an arenium ion (by breaking one of the N=O bonds).
Step-3) Finally the arenium ion loses a proton to a lewis base (to regain its aromaticity) and leads to the formation of our final product nitrobenzene (${C_6}{H_5}N{O_2}$).
Here we can see that we have replaced a hydrogen atom from the benzene ring with a strong electrophile (nitronium ion, $NO_2^ + $), and hence we can call nitration of benzene as an electrophilic substitution reaction.
So, the correct answer is “Option C”.
Note: An electrophile is an ion which is itself positively charged and gets attracted to electron rich atoms or molecules, while a nucleophile is an ion which itself is negatively charged and gets attracted to electron deficient atoms or compounds. So, in an electrophilic substitution reaction an electrophile replaces another electrophile.
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