Questions & Answers

Question

Answers

A. 4

B. 5

C. 6

D. 7

Answer
Verified

- Firstly, we have to write the equation between ammonia and oxygen in which the ammonia will reduce into nitrogen oxide:

$\text{4N}{{\text{H}}_{3}}\text{ + 5}{{\text{O}}_{2}}\text{ }\to \text{ 4NO + 6}{{\text{H}}_{2}}\text{O}$

- As we can see that the oxidation state of nitrogen changes from -3 to +2 so it undergoes oxidation reaction.

- But there are a total of 4 moles of ammonia and nitrogen oxide so the difference between the oxidation state of both is:

$\begin{align}& \left( 3\text{ }\cdot \text{ 4} \right)\text{ - }\left( \text{2 }\cdot \text{ 4} \right)\text{ = 12 - 8} \\ & \text{= 4} \\ \end{align}$

- So, the n-factor is 4.

- Now, we have to calculate the number of equivalents of ammonia so let's understand the definition of it i.e.

The number of equivalents is an amount of the electron or ions that can be transferred in a chemical reaction.

- So, here a total of 4 electrons are transferred from the reactant side to the product side.