Answer
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Hint: First we must know that the rate of diffusion is inversely proportional to the molecular mass of the gas. Because, two gas \[N{H_3}\] and \[HCl\]are diffusing with each other and forming \[N{H_4}Cl\] white ring.
Complete step by step answer:
First we will discuss what all are the possibilities in this question.
Let’s assume we have two gasses A and B which react to give a ring (just like the question) now in case 1, if the gas A diffuses faster than gas B then the ring will form near to B. In case 2, if the rate of diffusion is same for both A and B then the ring will be formed in the centre. And In case 3, if the gas B diffuses faster than A then the ring will be formed near A.
Now, the diffusibility of a gas is inversely proportional to the molecular mass of the gas.
In case of\[HCl\],
The molecular mass of the gas will be 1 (atomic mass of Hydrogen) + 35.5 (atomic mass of chlorine) = \[36.5{\text{ }}g/mol\](molecular mass of \[HCl\]).
Now in case of NH3,
The molecular mass will be 14 (atomic mass of Nitrogen) + 3 X 1 (atomic mass of hydrogen is 1 and there are 3 hydrogen’s) = \[17{\text{ }}g/mol\](molecular mass of\[N{H_3}\]).
Since the molecular mass of \[HCl\] is more than \[N{H_3}\], this means that the diffusibility of \[N{H_3}\] is greater than\[HCl\]. Hence, the White ring will appear nearer to the \[HCl\].
So, the answer to this question A i.e nearer to the \[HCl\] end.
Note:
We must know that the concept of diffusibility helps us determine how fast a gas reacts with other gas as well as tell us about the speed at which it moves from one place to another. A famous example for the same is diffusion of perfume, when one spray a perfume in one corner the odour of perfume reaches the other end of the room in seconds. This can be explained using the concept of diffusibility.
Complete step by step answer:
First we will discuss what all are the possibilities in this question.
Let’s assume we have two gasses A and B which react to give a ring (just like the question) now in case 1, if the gas A diffuses faster than gas B then the ring will form near to B. In case 2, if the rate of diffusion is same for both A and B then the ring will be formed in the centre. And In case 3, if the gas B diffuses faster than A then the ring will be formed near A.
Now, the diffusibility of a gas is inversely proportional to the molecular mass of the gas.
In case of\[HCl\],
The molecular mass of the gas will be 1 (atomic mass of Hydrogen) + 35.5 (atomic mass of chlorine) = \[36.5{\text{ }}g/mol\](molecular mass of \[HCl\]).
Now in case of NH3,
The molecular mass will be 14 (atomic mass of Nitrogen) + 3 X 1 (atomic mass of hydrogen is 1 and there are 3 hydrogen’s) = \[17{\text{ }}g/mol\](molecular mass of\[N{H_3}\]).
Since the molecular mass of \[HCl\] is more than \[N{H_3}\], this means that the diffusibility of \[N{H_3}\] is greater than\[HCl\]. Hence, the White ring will appear nearer to the \[HCl\].
So, the answer to this question A i.e nearer to the \[HCl\] end.
Note:
We must know that the concept of diffusibility helps us determine how fast a gas reacts with other gas as well as tell us about the speed at which it moves from one place to another. A famous example for the same is diffusion of perfume, when one spray a perfume in one corner the odour of perfume reaches the other end of the room in seconds. This can be explained using the concept of diffusibility.
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