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Name the Indian scientist who gave Bose-Einstein Statistics ?

Last updated date: 23rd Jul 2024
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Hint: Bose Einstein condensate is a state of matter in which separate subatomic particles or atoms, cooled to absolute zero. When that temperature is reached, the atoms hardly move relative to each other and they do not have free energy to move. At this point, the atoms start to clump together and they enter the same energy states. They all become identical from a physical point of view and the whole will begin to behave as it were a single atom.

Complete answer:
Bose Einstein condensate can be defined as the state of matter of a dilute gas of bosons which is cooled to a temperature that is very close to absolute zero. Bose Einstein condensate refers to breakdown of the atoms into a single quantum state. This state of matter was proposed by Satyendra Nath Bose and Albert Einstein.

It is a state of affairs which is made up of weakly interacting bosons at a temperature near absolute zero. When this temperature is reached, most bosons occupy the lowest quantum state of the external potential.

Therefore, the Indian scientist who gave Bose-Einstein Statistics is Satyendra Nath Bose.

Note: Bose started considering how the groups of photons behave in the year$1924$. Photons belong to one of the two great classes of elementary or submicroscopic particles that are defined by whether their quantum spin is a non-negative integer or an odd half integer. The former type are bosons. They include photons whose spin is one. The latter type are fermions which include electrons whose spin is $\dfrac{1}{2}$.