Question

How many more coordination isomers are possible of the compound $\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]\left[ {PtC{l_4}} \right]$?
A.3
B.4
C.6
D.8

Answer 1

Hint:We can say coordination isomers are two (or) more coordination compounds where the composition inside the coordination sphere i.e the metal atom and the ligands that are attached to it is different, that is connectivity between atoms are different.

Complete answer:
We have to remember that the coordination complex is a compound that has a central atom (ion) that is metallic and is known as the coordination centre. It is encircled by array bound molecules (or) ions called ligands (or) complexing agents. Transition metals are known to be coordination complexes. A coordination complex whose centre has a metal atom is called a metal complex of d block element.
Coordination isomerism takes place between compounds having complex anionic and cationic parts that could be thought of taking place by interchange of a few ligands from the cationic part to the anionic part. So, there are two complex compounds attached together, one contains negative charge and the other contains positive charge. The anion and cation complexes of a coordination compound interchange one or more ligands in coordination isomers.
The given coordination compound is,
$\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]\left[ {PtC{l_4}} \right]$
The isomers of the compound are,
$\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]\left[ {PtC{l_4}} \right]$
$\left[ {Cu{{\left( {N{H_3}} \right)}_3}Cl} \right]\left[ {Pt\left( {N{H_3}} \right)C{l_3}} \right]$
$\left[ {Cu{{\left( {N{H_3}} \right)}_2}C{l_2}} \right]\left[ {Pt{{\left( {N{H_3}} \right)}_2}C{l_2}} \right]$ two isomers possible here
$\left[ {Cu\left( {N{H_3}} \right)C{l_3}} \right]\left[ {Pt{{\left( {N{H_3}} \right)}_3}Cl} \right]$
$\left[ {CuC{l_4}} \right]\left[ {Pt{{\left( {N{H_3}} \right)}_4}} \right]$
So, totally there are six isomers for the compound $\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]\left[ {PtC{l_4}} \right]$.
Therefore, the option (C) is correct.

Note: We have to know that the other possible isomers in coordination compounds. Some other possible isomers are hydrate isomerism, linkage isomerism, stereoisomers isomerism, ionization isomerism.
We know that the compounds with identical molecular formula but differ in the arrangement of the atom are said to be isomers. We can say stereoisomers are the isomers that contain the same molecular formula but variation in spatial arrangement of atoms. Stereoisomers can be subdivided into two groups,
-Optical isomers
-Geometrical isomers.