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How many moles of $N{H_3}$are there in $250c{m^3}$ of a $30\%$ solution, the specific gravity of which is$0.90$?A. $3.97{\text{ }}moles$ B. $6.37{\text{ }}moles$ C. $3.70{\text{ }}moles$ D. $3.50{\text{ }}moles$

Last updated date: 19th Jun 2024
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Hint:We will take the help of the formula of Mass percentage. It is the amount of solute present in $100g$ of solution. By this we can find the number of moles i.e. the number of moles is the ratio of given weight of solute to the molar mass of the solute.
Formula used: Mass percentage$= \dfrac{{Mass{\text{ of solute}}}}{{Mass{\text{ of solution}}}} \times 100$

Given: Volume of water $= 250ml$
Density of water$= 0.999g/ml$
Since density $= \dfrac{{Mass{\text{ of water}}}}{{Volume{\text{ of water}}}}$
$6.999 = \dfrac{{Mass{\text{ of water}}}}{{250}} \\ \therefore Mass{\text{ of water}} = 0.999 \times 250 \\$
$= 249.75gm$
Since ammonia dissolved in ${H_2}O$ is $30\%$by weight
By using the formula, mass percentage$= \dfrac{{Mass{\text{ of solute}}}}{{Mass{\text{ of solution}}}} \times 100$
Mass percentage $= \dfrac{{Mass{\text{ of solute}}}}{{Mass{\text{ of solute}} + mass{\text{ of solvent}}}} \times 100$
$\therefore $$Mass{\text{ percentage}}$$ = \dfrac{{Mass{\text{ of ammonia}}}}{{Mass{\text{ of ammonia}} + mass{\text{ of water}}}} \times 100$
Now, let the mass of ammonia be mass percentage is $30\%$ and mass of water is $249.75gm,$by putting the values we will get-
$\dfrac{{30}}{{100}} = \dfrac{x}{{x + 249.75}}$
$30x + 7492.5 = 100x \\ 70x = 7492.5{\text{ }} \\ \therefore {\text{x = 107}}{\text{.03gm}}{\text{.}} \\$
Thus mass of ammonia dissolved in $250ml$ of water is $107.03gm$
To find the number of moles of ammonia we will use this formula
Number moles of $N{H_3} = \dfrac{{Mass{\text{ of ammonia}}}}{{Molar{\text{ mass}}}}$
$= \dfrac{{107.03g}}{{17g/mol}} \\ = 6.3moles \\$

Hence the correct answer is option B.

Note: it is very important to know how the amount of substance is expressed when it is present in the form of a solution. The concentration of a solution or the amount of substance present in its given volume can be expressed in any of the following ways: mass percentage, mole fraction, molality and normality. Mass percentage is independent of temperature.