Answer
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Hint: We know that sulphuric acid is a strong acid and potassium hydroxide is a strong base. Addition of a base to the acid makes the acid to reach a pH value of 7. If the solution reaches pH 7, then the reaction is called a neutralization reaction.
Complete step by step solution:
- In the question, it is given that to find the number of moles of potassium hydroxide required to neutralize 196 grams of sulphuric acid.
- The molecular formula of sulphuric acid is ${{H}_{2}}S{{O}_{4}}$.
- First, we have to write a balanced equation to get the information about the reaction.
- The reaction of sulphuric acid with potassium hydroxide is as follows.
\[2KOH+{{H}_{2}}S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]
- In the above reaction 2 moles of potassium hydroxide reacts with one mole of sulphuric acid and forms potassium sulphate and 2 moles of water as the products.
- Given that Molecular weight of sulphuric acid is 98 amu.
\[\underset{2moles}{\mathop{2KOH}}\,+\underset{98g}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\to {{K}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]
- As per the above equation 2 moles of potassium hydroxide reacts with 98 grams of sulphuric acid.
- In the question it is asked to find the number of moles of potassium hydroxide required to react with 196 grams of sulphuric acid.
- Then,
\[\begin{align}
& \text{2moles of KOH}\to \text{98 grams of sulphuric acid} \\
& \text{X moles of KOH}\to \text{196grams of sulphuric acid} \\
\end{align}\]
- We have to find X value.
- Thus,
\[\begin{align}
& \dfrac{\text{X moles}}{\text{2 moles}}\text{=}\dfrac{\text{196g}}{\text{98g}} \\
& \text{X=4 moles} \\
\end{align}\]
- Here X = number of moles of potassium hydroxide required to neutralize 196 grams of sulphuric acid.
- Therefore the number of moles of potassium hydroxide required to neutralize 196 grams of sulphuric acid is 4 moles.
So, the correct option is (D).
Note: amu means Atomic mass unit. Nothing but grams can be expressed in amu also. For 98 grams of sulphuric acid 2 moles of potassium hydroxide is sufficient to neutralize. If the amount of sulphuric acid is doubled the number of moles of potassium hydroxide required to neutralize also doubles.
Complete step by step solution:
- In the question, it is given that to find the number of moles of potassium hydroxide required to neutralize 196 grams of sulphuric acid.
- The molecular formula of sulphuric acid is ${{H}_{2}}S{{O}_{4}}$.
- First, we have to write a balanced equation to get the information about the reaction.
- The reaction of sulphuric acid with potassium hydroxide is as follows.
\[2KOH+{{H}_{2}}S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]
- In the above reaction 2 moles of potassium hydroxide reacts with one mole of sulphuric acid and forms potassium sulphate and 2 moles of water as the products.
- Given that Molecular weight of sulphuric acid is 98 amu.
\[\underset{2moles}{\mathop{2KOH}}\,+\underset{98g}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\to {{K}_{2}}S{{O}_{4}}+2{{H}_{2}}O\]
- As per the above equation 2 moles of potassium hydroxide reacts with 98 grams of sulphuric acid.
- In the question it is asked to find the number of moles of potassium hydroxide required to react with 196 grams of sulphuric acid.
- Then,
\[\begin{align}
& \text{2moles of KOH}\to \text{98 grams of sulphuric acid} \\
& \text{X moles of KOH}\to \text{196grams of sulphuric acid} \\
\end{align}\]
- We have to find X value.
- Thus,
\[\begin{align}
& \dfrac{\text{X moles}}{\text{2 moles}}\text{=}\dfrac{\text{196g}}{\text{98g}} \\
& \text{X=4 moles} \\
\end{align}\]
- Here X = number of moles of potassium hydroxide required to neutralize 196 grams of sulphuric acid.
- Therefore the number of moles of potassium hydroxide required to neutralize 196 grams of sulphuric acid is 4 moles.
So, the correct option is (D).
Note: amu means Atomic mass unit. Nothing but grams can be expressed in amu also. For 98 grams of sulphuric acid 2 moles of potassium hydroxide is sufficient to neutralize. If the amount of sulphuric acid is doubled the number of moles of potassium hydroxide required to neutralize also doubles.
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