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# How many moles are there in $24$ gram of $\text{Fe}{{\text{F}}_{\text{3}}}?$

Last updated date: 22nd Mar 2023
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Hint: Moles are calculated from the molecular weight. The mole is the unit of measurement for the amount of substance in the international system of units. It is defined as exactly $6.022\times {{10}^{23}}$ particles, which may be atoms, molecules, ions or electrons. The mole is widely used in chemistry as a connectional way to express amounts of red ants and products.

The number of grams of a mole is equal to the formula weight of a compound in atomic units.
Formula mass of substance can be calculated by summing the average atomic masses of all the atoms represented in the formula, here $\text{Fe}{{\text{F}}_{\text{3}}}$ .
We have the formula
Number of moles $=\dfrac{\text{Mass of substance}}{\text{Mass of one mole}}$
Mass of one mole $=$ molecular mass $=55.8+19+19+19=112.8$ g/mol
Therefore number of moles in $24$ grams of $\text{Fe}{{\text{F}}_{\text{3}}}$can be calculated as
Number of moles $=\dfrac{24}{112.8}=0.213$
Therefore $0.213$ moles are there in $24$ grams of $\text{Fe}{{\text{F}}_{\text{3}}}$.
Since Fe has molecular weight or atomic mass $=55.84$ & Fluorine has atomic mass $19.$ The average sum of mass of the $\text{Fe}{{\text{F}}_{\text{3}}}$comes out to be $112.8$ g/mol.

The term gram-molecule (gmol) was formerly used for mole of molecules and gram atom for mole of atoms. The history of the mole is intertwined with that of molecular, mass, atomic mass unit, and the Avogadro number. The Avogadro constant $NA$ is related to other physical constants and properties.
1. It relates molar gas constant & the Boltzman constant ${{K}_{B}}$
$R={{K}_{B}}{{N}_{A}}$
2. It relates the faraday constant $F$ and the elementary charge e.
$F=eNA$
3. It relates the molar mass constant, $Mu$ & atomic mass unit $mu.$
$Mu=muNA.$