Answer
Verified
394.8k+ views
Hint: At equilibrium the force exerted from the inside is balanced out by the tension experienced by the walls of the tube. Therefore, find the expressions for the previously mentioned forces and equate them to obtain an expression for the maximum internal pressure. Also remember to account for all tension points as a result of the applied force.
Complete answer:
Let us deconstruct the question and deduce the influencing parameters.
We have a thin walled tube with radius $r \Rightarrow$ diameter $d = 2r$ and thickness $\Delta r$.
Let the length of the tube be $L$.
An internal pressure $P$ causes tension $T$ in the walls of the tube. Therefore, the two forces at play are the force on the walls exerted by the internal pressure and the consequent tension produced in the tube walls,i.e.,
$F_{on\;walls} = P \times A = P \times 2\times r \times L$
The force acting on a point on the wall tries to elongate the tube along the axis of the applied force. This produces regions of stress at points perpendicular to the force direction. This stress produces tension, which is basically the reaction of the tube to the applied force, and is hence directed opposite to the direction of the applied force.
Now, since the stress here is associated with stretching forces, we can call it tensile stress. Thus, from the general equation for tensile stress we have:
Stress $\sigma = \dfrac{F}{A}$ and in this case, since the force acting on the tube walls ($\Delta r$) is tension, it becomes $\sigma = \dfrac{T}{A} \Rightarrow T=\sigma \times A = \sigma \times \Delta r \times L$
We have mentioned above that there will be two regions of stress produced at points perpendicular to force direction. As a consequence, the total tension produced on the tube walls will be $2T$
Now, breaking stress is the maximum stress that the tube can experience beyond which the tube will rupture. At this point, force from internal pressure(which is maximum) perfectly balances out the tension experienced by tube walls:
$F_{on\;walls} = 2T \Rightarrow P_{max} \times 2\times r \times L = 2 \times \sigma_{max} \times \Delta r \times L$
From this state of equilibrium, we can calculate the maximum internal pressure.
$P_{max} = \sigma_{max} \times \dfrac{\Delta r}{r}$
Therefore, the correct option would be B. $\sigma_{max} \times \dfrac{\Delta r}{r}$
Note:
While determining the magnitude of tension experienced as a result of a stretching force in one direction, it is important to remember that for a tube, the point force produces two stress points on the opposite sides of the circumference perpendicular to the direction of the applied force
Also recall that here we are considering only the tangential or circumferential stress since pressure acts inside the tube in all directions and is directed towards the circumference of the tube, and the tension thus produced is tangential.
Complete answer:
Let us deconstruct the question and deduce the influencing parameters.
We have a thin walled tube with radius $r \Rightarrow$ diameter $d = 2r$ and thickness $\Delta r$.
Let the length of the tube be $L$.
An internal pressure $P$ causes tension $T$ in the walls of the tube. Therefore, the two forces at play are the force on the walls exerted by the internal pressure and the consequent tension produced in the tube walls,i.e.,
$F_{on\;walls} = P \times A = P \times 2\times r \times L$
The force acting on a point on the wall tries to elongate the tube along the axis of the applied force. This produces regions of stress at points perpendicular to the force direction. This stress produces tension, which is basically the reaction of the tube to the applied force, and is hence directed opposite to the direction of the applied force.
Now, since the stress here is associated with stretching forces, we can call it tensile stress. Thus, from the general equation for tensile stress we have:
Stress $\sigma = \dfrac{F}{A}$ and in this case, since the force acting on the tube walls ($\Delta r$) is tension, it becomes $\sigma = \dfrac{T}{A} \Rightarrow T=\sigma \times A = \sigma \times \Delta r \times L$
We have mentioned above that there will be two regions of stress produced at points perpendicular to force direction. As a consequence, the total tension produced on the tube walls will be $2T$
Now, breaking stress is the maximum stress that the tube can experience beyond which the tube will rupture. At this point, force from internal pressure(which is maximum) perfectly balances out the tension experienced by tube walls:
$F_{on\;walls} = 2T \Rightarrow P_{max} \times 2\times r \times L = 2 \times \sigma_{max} \times \Delta r \times L$
From this state of equilibrium, we can calculate the maximum internal pressure.
$P_{max} = \sigma_{max} \times \dfrac{\Delta r}{r}$
Therefore, the correct option would be B. $\sigma_{max} \times \dfrac{\Delta r}{r}$
Note:
While determining the magnitude of tension experienced as a result of a stretching force in one direction, it is important to remember that for a tube, the point force produces two stress points on the opposite sides of the circumference perpendicular to the direction of the applied force
Also recall that here we are considering only the tangential or circumferential stress since pressure acts inside the tube in all directions and is directed towards the circumference of the tube, and the tension thus produced is tangential.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The branch of science which deals with nature and natural class 10 physics CBSE
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Select the word that is correctly spelled a Twelveth class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE