Answer
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Hint Malate plays an important role in biochemistry. The C4. In the carbon fixation process, malate is a source of CO in the Calvin cycle. In the citric acid cycle, malate is an intermediate formed by adding an OH group to the face of the fumarate. It is a compound of 4 C.
Complete answer:
The initiation step of the citric acid cycle occurs when a four-carbon compound condenses with acetyl-CoA to form citric acid (6 C). The purpose of a "spin" of the citric acid cycle is to produce two molecules of carbon dioxide. Glutaric acid is a 5C compound. It is produced naturally in the body during the metabolism of certain amino acids, including lysine and tryptophan.
Glycolysis, the starting stage of glucose metabolism, happens in the cytoplasm, and does not involve molecular O.of them. It gives a little quantity of ATP and the pyruvate which is a three-carbon compound.
Additional information:
Breakdown of Pyruvate: Pyruvate, the product of glycolysis, needs to forgo many changes to enter the next pathway process in order to become acetyl Coenzyme A (acetyl CoA). Acetyl CoA is a molecule that is next changed or converted to oxaloacetate, which further enters the citric acid cycle (Krebs cycle). This whole conversion of pyruvate to acetyl CoA is a three-step process.
So the correct answer is A-t, B-p, C-s, D-q.
Note: The acetyl carbons of acetyl CoA are released as carbon dioxide in the citric acid cycle decomposition of pyruvate.
The pyruvate, which is the product of glycolysis, in order to enter the next path, needs to have several changes for becoming acetyl coenzyme A (acetyl CoA). Acetyl CoA is a molecule that is furtherly converted to oxaloacetate, which enters the citric acid cycle (Krebs cycle). For the conversion of pyruvate to the acetyl CoA, three steps take place.
Acetyl CoA to CO2 Acetyl CoA acetyl carbons are released as carbon dioxide in the citric acid cycle
Complete answer:
The initiation step of the citric acid cycle occurs when a four-carbon compound condenses with acetyl-CoA to form citric acid (6 C). The purpose of a "spin" of the citric acid cycle is to produce two molecules of carbon dioxide. Glutaric acid is a 5C compound. It is produced naturally in the body during the metabolism of certain amino acids, including lysine and tryptophan.
Glycolysis, the starting stage of glucose metabolism, happens in the cytoplasm, and does not involve molecular O.of them. It gives a little quantity of ATP and the pyruvate which is a three-carbon compound.
Additional information:
Breakdown of Pyruvate: Pyruvate, the product of glycolysis, needs to forgo many changes to enter the next pathway process in order to become acetyl Coenzyme A (acetyl CoA). Acetyl CoA is a molecule that is next changed or converted to oxaloacetate, which further enters the citric acid cycle (Krebs cycle). This whole conversion of pyruvate to acetyl CoA is a three-step process.
So the correct answer is A-t, B-p, C-s, D-q.
Note: The acetyl carbons of acetyl CoA are released as carbon dioxide in the citric acid cycle decomposition of pyruvate.
The pyruvate, which is the product of glycolysis, in order to enter the next path, needs to have several changes for becoming acetyl coenzyme A (acetyl CoA). Acetyl CoA is a molecule that is furtherly converted to oxaloacetate, which enters the citric acid cycle (Krebs cycle). For the conversion of pyruvate to the acetyl CoA, three steps take place.
Acetyl CoA to CO2 Acetyl CoA acetyl carbons are released as carbon dioxide in the citric acid cycle
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