
What is the mass of
(1) $0.5$ mole of $C{O_2}$
(2) $2.5$ mole of $C{l_2}$
Answer
546.3k+ views
Hint: A mole is defined as the mass of the substance which contains ${N_A}$ number of particles of that substance. The number of moles of a species is given by the equation $n = \dfrac{m}{M}$. We will use this formula for calculating the mass in both the given cases.
Complete step by step answer:
We have been given the number of moles of carbon dioxide. Now by the formula $n = \dfrac{m}{M}$ where m is the mass of the substance
M is the molar mass of the substance
n is the number of moles
For the first case of carbon dioxide, the molecular mass is given by
The molar mass of carbon dioxide $ = $ Mass of carbon $ + $ $2$ (Mass of oxygen)
The molar mass of carbon dioxide =$12 + 2(16) = 12 + 32 = 44$ g/mol
Therefore the molar mass of carbon dioxide =$44$ g/mol
So putting these values in the given equation we get
$0.5 = \dfrac{m}{{44}}$
$ \Rightarrow m = 0.5 \times 44 = 22$ g
Therefore the mass of $0.5$ moles of carbon dioxide is $22$ g
Coming to the second question the molar mass of $C{l_2}$ is given by
Mass of $C{l_2}$ =$2$(Mass of chlorine atom)
$ \Rightarrow $ Mass of $C{l_2}$ =$2 \times 35.5 = 71$ g/mol
So substituting the given values in the formula we get
$2.5 = \dfrac{m}{{71}}$
$ \Rightarrow m = 71 \times 2.5 = 177.5$ gram
Therefore the mass of $2.5$ moles $C{l_2}$ is $177.5$ g
Note: We can solve it by another alternate method by the following way
We know that mass of one mole of carbon dioxide corresponds to $44$ g
Therefore the mass of $0.5$ a mole of carbon dioxide corresponds to $22$ g. Similarly, we can do it for chlorine
We know that the $C{l_2}$ molecule contains two chlorine atoms. The atomic mass of a chlorine atom is $35.5$
So the molar mass of $C{l_2}$ molecule will be $35.5 \times 2 = 71$ g
Now we know that mass of one mole of $C{l_2}$ corresponds to $71$ g
So the mass of $2.5$ mole will correspond to $2.5 \times 71 = 177.5$g
Mole is the count of a very large number of particles. It is a very beneficial unit for expressing the number of reactants and products present in the system.
Complete step by step answer:
We have been given the number of moles of carbon dioxide. Now by the formula $n = \dfrac{m}{M}$ where m is the mass of the substance
M is the molar mass of the substance
n is the number of moles
For the first case of carbon dioxide, the molecular mass is given by
The molar mass of carbon dioxide $ = $ Mass of carbon $ + $ $2$ (Mass of oxygen)
The molar mass of carbon dioxide =$12 + 2(16) = 12 + 32 = 44$ g/mol
Therefore the molar mass of carbon dioxide =$44$ g/mol
So putting these values in the given equation we get
$0.5 = \dfrac{m}{{44}}$
$ \Rightarrow m = 0.5 \times 44 = 22$ g
Therefore the mass of $0.5$ moles of carbon dioxide is $22$ g
Coming to the second question the molar mass of $C{l_2}$ is given by
Mass of $C{l_2}$ =$2$(Mass of chlorine atom)
$ \Rightarrow $ Mass of $C{l_2}$ =$2 \times 35.5 = 71$ g/mol
So substituting the given values in the formula we get
$2.5 = \dfrac{m}{{71}}$
$ \Rightarrow m = 71 \times 2.5 = 177.5$ gram
Therefore the mass of $2.5$ moles $C{l_2}$ is $177.5$ g
Note: We can solve it by another alternate method by the following way
We know that mass of one mole of carbon dioxide corresponds to $44$ g
Therefore the mass of $0.5$ a mole of carbon dioxide corresponds to $22$ g. Similarly, we can do it for chlorine
We know that the $C{l_2}$ molecule contains two chlorine atoms. The atomic mass of a chlorine atom is $35.5$
So the molar mass of $C{l_2}$ molecule will be $35.5 \times 2 = 71$ g
Now we know that mass of one mole of $C{l_2}$ corresponds to $71$ g
So the mass of $2.5$ mole will correspond to $2.5 \times 71 = 177.5$g
Mole is the count of a very large number of particles. It is a very beneficial unit for expressing the number of reactants and products present in the system.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

