Answer
Verified
424.8k+ views
Hint: Use the fact that if m be the number of elements in a set X and n be the number of elements in a set
Y, and if $n\ge m$, then the number of one-one functions from X to Y is given by the formula
$\dfrac{n!}{\left( n-m \right)!}$. Further use the fact that the total number of onto functions from a set X with m elements and another set Y with n elements, such that $m\ge n$ is given by the sum $\sum\limits_{k=0}^{n}{-{{1}^{k}}}\left( \begin{matrix} n \\ k \\
\end{matrix} \right){{\left( n-k \right)}^{m}}$. . These values of $\alpha $ and $\beta $ can then be used to calculate the required value of $\dfrac{1}{51}\left( \alpha -\beta \right)$.
Complete step by step solution:
For mapping functions from set X having 5 elements to set Y having 7 elements, these functions can be
either one-one or many-one. The total number of one-one functions can be calculated using the formula
$\dfrac{n!}{\left( n-m \right)!}$, where n is the number of elements in Y and m is the number of elements
in X.
Thus, for the given question, $m=5$ and $n=7$. Using these values in the formula, we get
$\begin{align}
& \alpha =\dfrac{7!}{\left( 7-5 \right)!} \\
& \Rightarrow \alpha =\dfrac{7!}{2!} \\
& \Rightarrow \alpha =7\times 6\times 5\times 4\times 3 \\
& \Rightarrow \alpha =2520 \\
\end{align}$
Thus, the required value of $\alpha $ is 2520.
For the calculation of $\beta $, consider the mapping of functions from Y to X. The total number of onto
functions from a set Y having m elements to another set X having n elements, where $m\ge n$ is given by
the formula $\sum\limits_{k=0}^{n}{-{{1}^{k}}}\left( \begin{matrix}
n \\
k \\
\end{matrix} \right){{\left( n-k \right)}^{m}}$.
Thus, we calculate this sum with \[m=7\] and \[n=5\] as
$\begin{align}
& \beta =\sum\limits_{k=0}^{5}{{{\left( -1 \right)}^{k}}}\left( \begin{matrix}
5 \\
k \\
\end{matrix} \right){{\left( 5-k \right)}^{7}} \\
& \Rightarrow \beta ={{\left( -1 \right)}^{0}}\left( \begin{matrix}
5 \\
0 \\
\end{matrix} \right){{\left( 5-0 \right)}^{7}}+{{\left( -1 \right)}^{1}}\left( \begin{matrix}
5 \\
1 \\
\end{matrix} \right){{\left( 5-1 \right)}^{7}}+{{\left( -1 \right)}^{2}}\left( \begin{matrix}
5 \\
2 \\
\end{matrix} \right){{\left( 5-2 \right)}^{7}}+{{\left( -1 \right)}^{3}}\left( \begin{matrix}
5 \\
3 \\
\end{matrix} \right){{\left( 5-3 \right)}^{7}} \\
& \ \ \ \ \ \ \ \ \ \ +{{\left( -1 \right)}^{4}}\left( \begin{matrix}
5 \\
4 \\
\end{matrix} \right){{\left( 5-4 \right)}^{7}}+{{\left( -1 \right)}^{5}}\left( \begin{matrix}
5 \\
5 \\
\end{matrix} \right){{\left( 5-5 \right)}^{7}} \\
& \Rightarrow \beta =1\times {{5}^{7}}-5\times {{4}^{7}}+10\times {{3}^{7}}-10\times
{{2}^{7}}+5\times {{1}^{7}} \\
& \Rightarrow \beta =5\left( {{5}^{6}}-{{4}^{7}} \right)+10\left( 2187-128 \right)+5 \\
& \Rightarrow \beta =5\left( 15625-16384 \right)+10\times 2059+5 \\
& \Rightarrow \beta =5\times \left( -759 \right)+20590+5 \\
& \Rightarrow \beta =20595-3795 \\
& \Rightarrow \beta =16800 \\
\end{align}$
Thus, the value of $\beta $ comes out to be 16800. This gives the value of $\dfrac{1}{51}\left( \beta -
\alpha \right)$ as
$\begin{align}
& \dfrac{1}{51}\left( \beta -\alpha \right)=\dfrac{1}{51}\left( 16800-2520 \right) \\
& \Rightarrow \dfrac{1}{51}\left( \beta -\alpha \right)=\dfrac{1}{51}\left( 14280 \right) \\
& \Rightarrow \dfrac{1}{51}\left( \beta -\alpha \right)=280 \\
\end{align}$
Thus the required value of $\dfrac{1}{51}\left( \beta -\alpha \right)$ is 280.
Note: The conditions for the calculation of one-one function and the calculation of the number of onto
functions are very important and to be kept in mind. These conditions, $n\ge m$ for one-one functions
and $m\ge n$ for onto functions is not only preliminary to the application of formulae but also necessary
for the existence of one-one and onto functions. If these conditions are violated, the number of one-one
functions and onto functions will both become 0 in their respective cases.
Y, and if $n\ge m$, then the number of one-one functions from X to Y is given by the formula
$\dfrac{n!}{\left( n-m \right)!}$. Further use the fact that the total number of onto functions from a set X with m elements and another set Y with n elements, such that $m\ge n$ is given by the sum $\sum\limits_{k=0}^{n}{-{{1}^{k}}}\left( \begin{matrix} n \\ k \\
\end{matrix} \right){{\left( n-k \right)}^{m}}$. . These values of $\alpha $ and $\beta $ can then be used to calculate the required value of $\dfrac{1}{51}\left( \alpha -\beta \right)$.
Complete step by step solution:
For mapping functions from set X having 5 elements to set Y having 7 elements, these functions can be
either one-one or many-one. The total number of one-one functions can be calculated using the formula
$\dfrac{n!}{\left( n-m \right)!}$, where n is the number of elements in Y and m is the number of elements
in X.
Thus, for the given question, $m=5$ and $n=7$. Using these values in the formula, we get
$\begin{align}
& \alpha =\dfrac{7!}{\left( 7-5 \right)!} \\
& \Rightarrow \alpha =\dfrac{7!}{2!} \\
& \Rightarrow \alpha =7\times 6\times 5\times 4\times 3 \\
& \Rightarrow \alpha =2520 \\
\end{align}$
Thus, the required value of $\alpha $ is 2520.
For the calculation of $\beta $, consider the mapping of functions from Y to X. The total number of onto
functions from a set Y having m elements to another set X having n elements, where $m\ge n$ is given by
the formula $\sum\limits_{k=0}^{n}{-{{1}^{k}}}\left( \begin{matrix}
n \\
k \\
\end{matrix} \right){{\left( n-k \right)}^{m}}$.
Thus, we calculate this sum with \[m=7\] and \[n=5\] as
$\begin{align}
& \beta =\sum\limits_{k=0}^{5}{{{\left( -1 \right)}^{k}}}\left( \begin{matrix}
5 \\
k \\
\end{matrix} \right){{\left( 5-k \right)}^{7}} \\
& \Rightarrow \beta ={{\left( -1 \right)}^{0}}\left( \begin{matrix}
5 \\
0 \\
\end{matrix} \right){{\left( 5-0 \right)}^{7}}+{{\left( -1 \right)}^{1}}\left( \begin{matrix}
5 \\
1 \\
\end{matrix} \right){{\left( 5-1 \right)}^{7}}+{{\left( -1 \right)}^{2}}\left( \begin{matrix}
5 \\
2 \\
\end{matrix} \right){{\left( 5-2 \right)}^{7}}+{{\left( -1 \right)}^{3}}\left( \begin{matrix}
5 \\
3 \\
\end{matrix} \right){{\left( 5-3 \right)}^{7}} \\
& \ \ \ \ \ \ \ \ \ \ +{{\left( -1 \right)}^{4}}\left( \begin{matrix}
5 \\
4 \\
\end{matrix} \right){{\left( 5-4 \right)}^{7}}+{{\left( -1 \right)}^{5}}\left( \begin{matrix}
5 \\
5 \\
\end{matrix} \right){{\left( 5-5 \right)}^{7}} \\
& \Rightarrow \beta =1\times {{5}^{7}}-5\times {{4}^{7}}+10\times {{3}^{7}}-10\times
{{2}^{7}}+5\times {{1}^{7}} \\
& \Rightarrow \beta =5\left( {{5}^{6}}-{{4}^{7}} \right)+10\left( 2187-128 \right)+5 \\
& \Rightarrow \beta =5\left( 15625-16384 \right)+10\times 2059+5 \\
& \Rightarrow \beta =5\times \left( -759 \right)+20590+5 \\
& \Rightarrow \beta =20595-3795 \\
& \Rightarrow \beta =16800 \\
\end{align}$
Thus, the value of $\beta $ comes out to be 16800. This gives the value of $\dfrac{1}{51}\left( \beta -
\alpha \right)$ as
$\begin{align}
& \dfrac{1}{51}\left( \beta -\alpha \right)=\dfrac{1}{51}\left( 16800-2520 \right) \\
& \Rightarrow \dfrac{1}{51}\left( \beta -\alpha \right)=\dfrac{1}{51}\left( 14280 \right) \\
& \Rightarrow \dfrac{1}{51}\left( \beta -\alpha \right)=280 \\
\end{align}$
Thus the required value of $\dfrac{1}{51}\left( \beta -\alpha \right)$ is 280.
Note: The conditions for the calculation of one-one function and the calculation of the number of onto
functions are very important and to be kept in mind. These conditions, $n\ge m$ for one-one functions
and $m\ge n$ for onto functions is not only preliminary to the application of formulae but also necessary
for the existence of one-one and onto functions. If these conditions are violated, the number of one-one
functions and onto functions will both become 0 in their respective cases.
Recently Updated Pages
Assertion The resistivity of a semiconductor increases class 13 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
What are the possible quantum number for the last outermost class 11 chemistry CBSE
Is C2 paramagnetic or diamagnetic class 11 chemistry CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Summary of the poem Where the Mind is Without Fear class 8 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Write an application to the principal requesting five class 10 english CBSE
What organs are located on the left side of your body class 11 biology CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE