
Let ${T_n}$ be the number of all possible triangles formed by joining vertices of an n-sided regular polygon. If ${T_{n + 1}} - {T_n} = 10$, then the value of n is?
(A). 5
(B). 10
(C). 8
(D). 7
Answer
508.8k+ views
Hint: Start by forming the term by selecting 3 sides for triangle out of n sides of a polygon, follow the same for (n+1) sided polygon. Substitute the value in the given equation and apply the relevant formulas of combination in order to get the desired value of n (neglect any negative value).
Complete step-by-step answer:
Step by step solution
Given, ${T_{n + 1}} - {T_n} = 10$
${T_n}$is the number of all possible triangles formed by joining vertices of n sided polygon.
And we know that for any triangle to be formed we need 3 sides of any polygon. Therefore , selecting 3 sides out of n sides can be done in ${}^n{C_3}$ways.
$\therefore {T_n} = {}^n{C_3}$
Similarly , if we have (n+1) sided polygon ,we can select 3 sides out of it in ${}^{n + 1}{C_3}$ ways.
$\therefore {T_{n + 1}} = {}^{n + 1}{C_3}$
Now , let us solve for the relation ${T_{n + 1}} - {T_n} = 10$and find out n value.
$
{T_{n + 1}} - {T_n} = 10 \\
\Rightarrow {}^{n + 1}{C_3} - {}^n{C_3} = 10 \\
$
And we know , ${}^n{C_r} + {}^n{C_{r - 1}} = {}^{n + 1}{C_r}$ . Applying this formula in the equation , we get
$
\Rightarrow {}^{n + 1}{C_3} - {}^n{C_3} = 10 \\
\Rightarrow {}^n{C_2} + {}^n{C_3} - {}^n{C_3} = 10 \\
\Rightarrow {}^n{C_2} = 10 \\
$
We know that ${}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}}$, Applying this formula
$
\Rightarrow \dfrac{{n!}}{{2!\left( {n - 2} \right)!}} = 10 \\
\Rightarrow \dfrac{{n \times (n - 1) \times (n - 2)!}}{{2!\left( {n - 2} \right)!}} = 10 \\
\Rightarrow n \times (n - 1) = 20 \\
\Rightarrow {n^2} - n - 20 = 0 \\
$
Splitting the middle term ,we get
$
{n^2} - 5n + 4n - 20 = 0 \\
\Rightarrow n(n - 5) + 4(n - 5) = 0 \\
\Rightarrow (n - 5)(n + 4) = 0 \\
\Rightarrow n = 5, - 4 \\
$
As n can never have a negative value , so we’ll neglect -4.
Therefore , the value of n=5.
So , option A is the correct answer.
Note: All the formulas used in combination must be well known , as such formulas are very important and help in solving the question faster. Also, attention needs to be given while substituting the values and solving the quadratic equations if any. Any negative value of n or r must be neglected as they can never be negative.
Complete step-by-step answer:
Step by step solution
Given, ${T_{n + 1}} - {T_n} = 10$
${T_n}$is the number of all possible triangles formed by joining vertices of n sided polygon.
And we know that for any triangle to be formed we need 3 sides of any polygon. Therefore , selecting 3 sides out of n sides can be done in ${}^n{C_3}$ways.
$\therefore {T_n} = {}^n{C_3}$
Similarly , if we have (n+1) sided polygon ,we can select 3 sides out of it in ${}^{n + 1}{C_3}$ ways.
$\therefore {T_{n + 1}} = {}^{n + 1}{C_3}$
Now , let us solve for the relation ${T_{n + 1}} - {T_n} = 10$and find out n value.
$
{T_{n + 1}} - {T_n} = 10 \\
\Rightarrow {}^{n + 1}{C_3} - {}^n{C_3} = 10 \\
$
And we know , ${}^n{C_r} + {}^n{C_{r - 1}} = {}^{n + 1}{C_r}$ . Applying this formula in the equation , we get
$
\Rightarrow {}^{n + 1}{C_3} - {}^n{C_3} = 10 \\
\Rightarrow {}^n{C_2} + {}^n{C_3} - {}^n{C_3} = 10 \\
\Rightarrow {}^n{C_2} = 10 \\
$
We know that ${}^n{C_r} = \dfrac{{n!}}{{r!\left( {n - r} \right)!}}$, Applying this formula
$
\Rightarrow \dfrac{{n!}}{{2!\left( {n - 2} \right)!}} = 10 \\
\Rightarrow \dfrac{{n \times (n - 1) \times (n - 2)!}}{{2!\left( {n - 2} \right)!}} = 10 \\
\Rightarrow n \times (n - 1) = 20 \\
\Rightarrow {n^2} - n - 20 = 0 \\
$
Splitting the middle term ,we get
$
{n^2} - 5n + 4n - 20 = 0 \\
\Rightarrow n(n - 5) + 4(n - 5) = 0 \\
\Rightarrow (n - 5)(n + 4) = 0 \\
\Rightarrow n = 5, - 4 \\
$
As n can never have a negative value , so we’ll neglect -4.
Therefore , the value of n=5.
So , option A is the correct answer.
Note: All the formulas used in combination must be well known , as such formulas are very important and help in solving the question faster. Also, attention needs to be given while substituting the values and solving the quadratic equations if any. Any negative value of n or r must be neglected as they can never be negative.
Recently Updated Pages
Master Class 12 Biology: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Trending doubts
Father of Indian ecology is a Prof R Misra b GS Puri class 12 biology CBSE

Who is considered as the Father of Ecology in India class 12 biology CBSE

Enzymes with heme as prosthetic group are a Catalase class 12 biology CBSE

An example of ex situ conservation is a Sacred grove class 12 biology CBSE

An orchid growing as an epiphyte on a mango tree is class 12 biology CBSE

Briefly mention the contribution of TH Morgan in g class 12 biology CBSE
