Answer
405k+ views
Hint: The ratio of the difference of the boiling temperature and the freezing temperature in the mentioned scale in question to the difference of the boiling temperature and the freezing temperature in the degree Celsius scale will be equivalent to the ratio of difference of the temperature which is to be calculated and the corresponding temperature in degree Celsius scale to the corresponding temperature in degree Celsius scale. This will help you in answering this question.
Complete step by step answer:
it has been given in the question that the freezing point of the water is,
\[{{T}_{f}}=25{}^\circ P\]
The boiling point of the water has been given in the question as,
\[{{T}_{b}}=225{}^\circ P\]
As we all know, the ratio of the difference of the boiling temperature and the freezing temperature in the mentioned scale in question to the difference of the boiling temperature and the freezing temperature in the degree Celsius scale will be equivalent to the ratio of difference of the temperature which is to be calculated and the corresponding temperature in degree Celsius scale to the corresponding temperature in degree Celsius scale. That is we can write that,
\[\dfrac{{{T}_{b}}-{{T}_{f}}}{100{}^\circ C-0{}^\circ C}=\dfrac{T-25{}^\circ C}{25{}^\circ C}\]
Substituting the values in it will give,
\[\dfrac{225-25}{100{}^\circ C-0{}^\circ C}=\dfrac{T-25{}^\circ C}{25{}^\circ C}\]
Simplifying the equation can be written as,
\[\begin{align}
& \dfrac{200}{100}=\dfrac{T-25{}^\circ C}{25} \\
& \Rightarrow 2=\dfrac{T-25{}^\circ C}{25} \\
\end{align}\]
Rearranging this equation will give,
\[\begin{align}
& 50=T-25 \\
& \therefore T=75{}^\circ P \\
\end{align}\]
So, the correct answer is “Option B”.
Note: The degree Celsius is defined as a unit of temperature on the Celsius scale. This temperature scale is otherwise called the centigrade scale. The degree Celsius can be considered to a particular temperature on the Celsius scale or a unit to represent a difference between two temperatures.
Complete step by step answer:
it has been given in the question that the freezing point of the water is,
\[{{T}_{f}}=25{}^\circ P\]
The boiling point of the water has been given in the question as,
\[{{T}_{b}}=225{}^\circ P\]
As we all know, the ratio of the difference of the boiling temperature and the freezing temperature in the mentioned scale in question to the difference of the boiling temperature and the freezing temperature in the degree Celsius scale will be equivalent to the ratio of difference of the temperature which is to be calculated and the corresponding temperature in degree Celsius scale to the corresponding temperature in degree Celsius scale. That is we can write that,
\[\dfrac{{{T}_{b}}-{{T}_{f}}}{100{}^\circ C-0{}^\circ C}=\dfrac{T-25{}^\circ C}{25{}^\circ C}\]
Substituting the values in it will give,
\[\dfrac{225-25}{100{}^\circ C-0{}^\circ C}=\dfrac{T-25{}^\circ C}{25{}^\circ C}\]
Simplifying the equation can be written as,
\[\begin{align}
& \dfrac{200}{100}=\dfrac{T-25{}^\circ C}{25} \\
& \Rightarrow 2=\dfrac{T-25{}^\circ C}{25} \\
\end{align}\]
Rearranging this equation will give,
\[\begin{align}
& 50=T-25 \\
& \therefore T=75{}^\circ P \\
\end{align}\]
So, the correct answer is “Option B”.
Note: The degree Celsius is defined as a unit of temperature on the Celsius scale. This temperature scale is otherwise called the centigrade scale. The degree Celsius can be considered to a particular temperature on the Celsius scale or a unit to represent a difference between two temperatures.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)