Question

# Iso-propyl bromide on Wurtz reaction gives:(A) Hexane(B) Propane(C) 2,3-dimethyl butane(D) Neo-hexane

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Hint:
The structure of isopropyl group is

Wurtz reaction gives Sodium halide as a side product in the reaction.

Let’s first see what happens in the Wurtz reaction.
In Wurtz reaction, two alkyl halides couple in presence of sodium metal and give alkane and sodium halide in ether solvent. The reaction can be written as,
$2R - X\xrightarrow[{Ether}]{{Na}}R - R + NaX$

Now let’s see the structure of isopropyl bromide.

So, if isopropyl bromide will be allowed to react with Sodium metal in ether solvent then, sodium metal will act as an reducing agent and will form a salt sodium bromide. Then the two isopropyl groups will combine and will give an alkane as a final product. So, the reaction can be written as below.

So, we can conclude that 2,3-dimethylbutane is the final product of the reaction.

Therefore the correct answer is (C) 2,3-dimethyl butane.

$2Ar - X\xrightarrow[{Ether}]{{Na}}Ar - Ar + NaX$
$R - X + Ar - X\xrightarrow[{Ether}]{{Na}}Ar - R + NaX$
Do not get confused by two other same looking reactions like Wurtz reaction, which is Fittig reaction and Wurtz –Fittig reaction. Remember that in the isopropyl group, the substituent group will get bonded with the ${2^{nd}}$ carbon of the group, so do not get confused with the n-propyl group.